To determine the [tex]\( y \)[/tex]-intercept of the line given by the equation [tex]\( y = -6x - 3 \)[/tex], we need to recall the standard form of a linear equation in slope-intercept form, which is:
[tex]\[ y = mx + b \][/tex]
Here, [tex]\( m \)[/tex] represents the slope of the line, and [tex]\( b \)[/tex] represents the [tex]\( y \)[/tex]-intercept.
In the given equation [tex]\( y = -6x - 3 \)[/tex]:
- The coefficient of [tex]\( x \)[/tex] is [tex]\(-6\)[/tex], which is the slope [tex]\( m \)[/tex].
- The constant term [tex]\(-3\)[/tex] corresponds to [tex]\( b \)[/tex], which is the [tex]\( y \)[/tex]-intercept.
Thus, the [tex]\( y \)[/tex]-intercept of the line [tex]\( y = -6x - 3 \)[/tex] is:
[tex]\[ b = -3 \][/tex]
So, the correct answer is:
A. -3
