To determine the number of oxygen atoms in 0.5 moles of anhydrous sodium sulfate (Na₂SO₄), let's go through the steps systematically:
1. Identify the molecular composition of sodium sulfate (Na₂SO₄):
- Each molecule of sodium sulfate contains 2 sodium (Na) atoms, 1 sulfur (S) atom, and 4 oxygen (O) atoms.
2. Given quantity:
- We have 0.5 moles of sodium sulfate (Na₂SO₄).
3. Determine the total number of oxygen atoms in the given moles:
- Since one molecule of sodium sulfate (Na₂SO₄) contains 4 oxygen atoms, each mole of sodium sulfate contains 4 moles of oxygen atoms.
- Therefore, in 0.5 moles of Na₂SO₄, the number of moles of oxygen atoms is calculated as follows:
[tex]\[
\text{Total moles of oxygen atoms} = 0.5 \, \text{moles of Na₂SO₄} \times 4 \, \text{oxygen atoms per Na₂SO₄}
\][/tex]
[tex]\[
\text{Total moles of oxygen atoms} = 2 \, \text{moles of O}
\][/tex]
4. Use Avogadro's number to convert moles of oxygen atoms to the number of oxygen atoms:
- Avogadro's number is 6.022 x 10²³, which is the number of atoms or molecules per mole.
- To find the total number of oxygen atoms in 2 moles, we proceed as follows:
[tex]\[
\text{Number of oxygen atoms} = 2 \, \text{moles of O} \times 6.022 \times 10^{23} \, \text{atoms/mole}
\][/tex]
[tex]\[
\text{Number of oxygen atoms} = 1.2044 \times 10^{24} \, \text{atoms}
\][/tex]
Final answer:
- There are [tex]\(2\)[/tex] moles of oxygen atoms.
- This corresponds to [tex]\(1.2044 \times 10^{24}\)[/tex] oxygen atoms.
Thus, in 0.5 moles of anhydrous sodium sulfate (Na₂SO₄), there are [tex]\(2\)[/tex] moles of oxygen atoms and a total of [tex]\(1.2044 \times 10^{24}\)[/tex] oxygen atoms.
