Sure, let's understand the process of the second meiotic division to determine the correct answer.
Meiosis is a type of cell division that reduces the chromosome number by half, resulting in four haploid cells (gametes). It consists of two sequential divisions: meiosis I and meiosis II.
1. Meiosis I:
- This is the reductional division, where homologous chromosomes (each consisting of two sister chromatids) are separated.
- It reduces the chromosome number from diploid (2n) to haploid (1n).
- At the end of meiosis I, you have two haploid cells, each containing chromosomes that still consist of two sister chromatids.
2. Meiosis II:
- This is similar to mitosis and is known as the equational division.
- In meiosis II, the sister chromatids are separated, resulting in haploid cells.
Let's examine the cellular state before and after the second meiotic division:
- The cells start as haploid (1n) after meiosis I.
- In meiosis II, each of these haploid cells divides again, separating the sister chromatids.
- The result is that each original haploid cell (1n) divides to produce two haploid cells (1n each).
Therefore, the second meiotic division causes each haploid cell (1n) to produce two haploid cells (1n each).
Thus, the correct answer is:
b) [tex]$1 n \rightarrow 1 n$[/tex]
