25. Simplify: [tex]\frac{1}{2}(x-1)-\frac{1}{3}\left(\frac{1}{2} x-1\right)[/tex].

A. [tex]\quad \frac{1}{6}(x-1)[/tex]
B. [tex]\frac{1}{6}(2 x+1)[/tex]
C. [tex]\quad \frac{1}{6}(2 x-1)[/tex]
D. [tex]\frac{1}{6}(1-2 x)[/tex]



Answer :

To simplify the expression [tex]\(\frac{1}{2}(x-1)-\frac{1}{3}\left(\frac{1}{2} x-1\right)\)[/tex], let's break it down step by step:

1. Distribute the constants inside the parentheses:
[tex]\[ \frac{1}{2}(x - 1) = \frac{1}{2}x - \frac{1}{2} \][/tex]
[tex]\[ \frac{1}{3}\left(\frac{1}{2} x - 1\right) = \frac{1}{3} \cdot \frac{1}{2} x - \frac{1}{3} \cdot 1 = \frac{1}{6} x - \frac{1}{3} \][/tex]

2. Rewrite the expression using these results:
[tex]\[ \frac{1}{2}x - \frac{1}{2} - \left(\frac{1}{6}x - \frac{1}{3}\right) \][/tex]

3. Distribute the negative sign to the terms inside the parenthesis:
[tex]\[ \frac{1}{2}x - \frac{1}{2} - \frac{1}{6}x + \frac{1}{3} \][/tex]

4. Combine like terms:
- Combine [tex]\( \frac{1}{2}x \)[/tex] and [tex]\(- \frac{1}{6}x \)[/tex]:
[tex]\[ \frac{1}{2}x - \frac{1}{6}x = \frac{3}{6}x - \frac{1}{6}x = \frac{2}{6}x = \frac{1}{3}x \][/tex]
- Combine [tex]\(-\frac{1}{2}\)[/tex] and [tex]\(+\frac{1}{3}\)[/tex]:
[tex]\[ -\frac{1}{2} + \frac{1}{3} = -\frac{3}{6} + \frac{2}{6} = -\frac{1}{6} \][/tex]

5. Put the simplified terms together:
[tex]\[ \frac{1}{3}x - \frac{1}{6} \][/tex]

So, the simplified form of the expression [tex]\(\frac{1}{2}(x-1)-\frac{1}{3}\left(\frac{1}{2} x-1\right)\)[/tex] is:

[tex]\[ \boxed{\frac{1}{3}x - \frac{1}{6}} \][/tex]

By analyzing the given answer choices, option C matches our simplified result:

C. [tex]\(\frac{1}{6}(2x - 1)\)[/tex]

This expression simplified can be written as:

[tex]\[ \frac{2x - 1}{6} = \frac{1}{3}x - \frac{1}{6} \][/tex]

Thus, the correct answer is:

C. [tex]\(\frac{1}{6}(2 x - 1)\)[/tex]