Sure, let's break this down step by step.
### Explanation
The statement that the specific heat capacity of water is 4200 J/kg K means that it takes 4200 joules of energy to raise the temperature of 1 kilogram of water by 1 degree Kelvin (or 1 degree Celsius, since the scale difference in increments is the same).
#### To verify this statement by experiment, you could:
1. Measure a known mass (m) of water, e.g., 1 kg.
2. Measure its initial temperature (T1).
3. Supply a known quantity of energy (Q) to the water using an electric heater.
4. Measure the final temperature (T2) of the water after the energy has been supplied.
5. Using the formula for specific heat capacity:
[tex]\[
\text{Specific Heat Capacity} = \frac{Q}{m \cdot (T2 - T1)}
\][/tex]
If the resulting value is close to 4200 J/kg K, the specific heat capacity value is verified.
### Calculation of heat produced by the kettle
To calculate the heat produced by the kettle, we need to know the power output of the kettle and the time for which it was operating.
1. Power of the kettle (P): 2250 watts (W)
2. Time of operation (t): 150 seconds (s)
The heat [tex]\( Q \)[/tex] produced can be calculated using the relationship:
[tex]\[
Q = P \times t
\][/tex]
Substituting the given values:
[tex]\[
Q = 2250 \, \text{W} \times 150 \, \text{s}
\][/tex]
After performing the multiplication, we find:
[tex]\[
Q = 337500 \, \text{Joules (J)}
\][/tex]
Thus:
(i) The heat produced by the kettle in this time is 337500 Joules (J).
