3. [2009] Which substance contains the same number of atoms as in [tex]$12 \, g$[/tex] of carbon? [H=1, C=12, O=16, Mg=24, S=32]

A. 2 g of hydrogen
B. [tex]$12 \, g$[/tex] of magnesium
C. [tex][tex]$22 \, g$[/tex][/tex] of carbon dioxide
D. [tex]$32 \, g$[/tex] of sulphur



Answer :

To determine which substance contains the same number of atoms as in 12 g of carbon ([tex]$C$[/tex]), we need to follow these steps:

1. Determine the number of moles of carbon in 12 g:
The atomic mass of carbon ([tex]$C$[/tex]) is given as 12 g/mol. Therefore, the number of moles in 12 g of carbon is:
[tex]\[ \text{moles of C} = \frac{12 \text{ g}}{12 \text{ g/mol}} = 1 \text{ mole} \][/tex]

2. Find the mass of each substance that contains the same number of moles (1 mole) as the carbon atoms:
- For hydrogen ([tex]$H$[/tex]) with an atomic mass of 1 g/mol:
[tex]\[ \text{mass of H} = 1 \text{ mole} \times 1 \text{ g/mol} = 1 \text{ g} \][/tex]
- For magnesium ([tex]$Mg$[/tex]) with an atomic mass of 24 g/mol:
[tex]\[ \text{mass of Mg} = 1 \text{ mole} \times 24 \text{ g/mol} = 24 \text{ g} \][/tex]
- For carbon dioxide ([tex]$CO_2$[/tex]), we need to consider its molar mass:
[tex]\[ \text{Molar mass of CO}_2 = \text{Atomic mass of C} + 2 \times \text{Atomic mass of O} = 12 \text{ g/mol} + 2 \times 16 \text{ g/mol} = 44 \text{ g/mol} \][/tex]
Thus, the mass of 1 mole of [tex]$CO_2$[/tex]:
[tex]\[ \text{mass of } CO_2 = 1 \text{ mole} \times 44 \text{ g/mol} = 44 \text{ g} \][/tex]
- For sulfur ([tex]$S$[/tex]) with an atomic mass of 32 g/mol:
[tex]\[ \text{mass of S} = 1 \text{ mole} \times 32 \text{ g/mol} = 32 \text{ g} \][/tex]

3. Compare these masses with the given options:
- Option (a): 2 g of hydrogen
- We calculated that 1 mole of hydrogen is 1 g. Hence, 2 g of hydrogen contains 2 moles.
- Option (b): 12 g of magnesium
- We calculated that 1 mole of magnesium is 24 g. Hence, 12 g of magnesium contains [tex]\( \frac{12}{24} = 0.5 \)[/tex] moles.
- Option (c): 22 g of carbon dioxide
- We calculated that 1 mole of carbon dioxide is 44 g. Hence, 22 g of carbon dioxide contains [tex]\( \frac{22}{44} = 0.5 \)[/tex] moles.
- Option (d): 32 g of sulphur
- We calculated that 1 mole of sulfur is 32 g. Hence, 32 g of sulfur contains 1 mole, which is the same as the 1 mole of carbon in 12 g of carbon.

Conclusion: The correct answer is:

d. 32 g of sulphur

This is because 32 g of sulfur contains the same number of atoms as 12 g of carbon, which is 1 mole.