\begin{tabular}{|c|c|}
\hline
[tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline
-2 & 6 \\
\hline
0 & 3.5 \\
\hline
2 & 1 \\
\hline
4 & -1.5 \\
\hline
\end{tabular}

Which equations represent the data in the table? Check all that apply.

A. [tex]$y-6=\frac{-5}{4}(x+2)$[/tex]

B. [tex]$y-2=-\frac{5}{4}(x-1)$[/tex]

C. [tex]$y+2=\frac{-5}{4}(x-6)$[/tex]

D. [tex]$y-1=-\frac{5}{4}(x-2)$[/tex]

E. [tex]$y-3.5=-1.25 x$[/tex]



Answer :

To determine which equations accurately represent the data in the given table, we need to substitute each data pair [tex]\((x, y)\)[/tex] into each equation and check if the equation holds true.

Let's go through each equation step-by-step:

1. First Equation: [tex]\( y - 6 = \frac{-5}{4}(x + 2) \)[/tex]

We will substitute each [tex]\((x, y)\)[/tex] pair:

- For [tex]\((x = -2, y = 6)\)[/tex]:
[tex]\[ 6 - 6 = \frac{-5}{4}(-2 + 2) \Rightarrow 0 = 0 \quad \text{(This is true)} \][/tex]

Since this pair satisfies the equation, it represents the data.

2. Second Equation: [tex]\( y - 2 = \frac{-5}{4}(x - 1) \)[/tex]

Let's substitute each [tex]\((x, y)\)[/tex] pair:

- For [tex]\((x = 0, y = 3.5)\)[/tex]:
[tex]\[ 3.5 - 2 = \frac{-5}{4}(0 - 1) \Rightarrow 1.5 = 1.25 \quad \text{(This is false)} \][/tex]

- For [tex]\((x = 2, y = 1)\)[/tex]:
[tex]\[ 1 - 2 = \frac{-5}{4}(2 - 1) \Rightarrow -1 = -1.25 \quad \text{(This is false)} \][/tex]

None of the pairs satisfy the equation, so it does not represent the data.

3. Third Equation: [tex]\( y + 2 = \frac{-5}{4}(x - 6) \)[/tex]

Substituting each [tex]\((x, y)\)[/tex] pair:

- For [tex]\((x = 0, y = 3.5)\)[/tex]:
[tex]\[ 3.5 + 2 = \frac{-5}{4}(0 - 6) \Rightarrow 5.5 = 7.5 \quad \text{(This is false)} \][/tex]

- For [tex]\((x = 2, y = 1)\)[/tex]:
[tex]\[ 1 + 2 = \frac{-5}{4}(2 - 6) \Rightarrow 3 = 5 \quad \text{(This is false)} \][/tex]

None of the pairs satisfy the equation, so it does not represent the data.

4. Fourth Equation: [tex]\( y - 1 = \frac{-5}{4}(x - 2) \)[/tex]

Substituting each [tex]\((x, y)\)[/tex] pair:

- For [tex]\((x = 2, y = 1)\)[/tex]:
[tex]\[ 1 - 1 = \frac{-5}{4}(2 - 2) \Rightarrow 0 = 0 \quad \text{(This is true)} \][/tex]

Since this pair satisfies the equation, it represents the data.

5. Fifth Equation: [tex]\( y - 3.5 = -1.25 x \)[/tex]

Substituting each [tex]\((x, y)\)[/tex] pair:

- For [tex]\((x = 0, y = 3.5)\)[/tex]:
[tex]\[ 3.5 - 3.5 = -1.25(0) \Rightarrow 0 = 0 \quad \text{(This is true)} \][/tex]

Since this pair satisfies the equation, it represents the data.

In summary, the equations that represent the data in the table are:
[tex]\[ y - 6 = \frac{-5}{4}(x + 2) \][/tex]
[tex]\[ y - 1 = \frac{-5}{4}(x - 2) \][/tex]
[tex]\[ y - 3.5 = -1.25 x \][/tex]

Thus, the equations that apply are the first, fourth, and fifth equations.