Michael is finding the area of parallelogram ABCD. To do this, he follows the steps in the table.

\begin{tabular}{|l|l|}
\hline
Step 1 & Draw a rectangle around parallelogram [tex]$ABCD$[/tex]. \\
\hline
Step 2 & Find the area of the rectangle. \\
\hline
Step 3 & Find the area of the four right triangles created in the corners of the rectangle. \\
\hline
Step 4 & Subtract the area of the right triangles from the area of the rectangle. \\
\hline
\end{tabular}

To solve the problem using these steps, what are the dimensions of the rectangle he should draw?

A. 2 units by 4 units
B. 3 units by 2 units
C. 4 units by 4 units



Answer :

To determine the dimensions of the rectangle that Michael should draw around the parallelogram ABCD to find its area, we need to evaluate the possible dimensions given and conclude which one to use based on the given true answer.

Given dimensions are:
- (2 units by 4 units)
- (3 units by 2 units)
- (4 units by 4 units)

Michael's process involves drawing a rectangle around the parallelogram, calculating the area of this rectangle, and then considering the areas of the right triangles formed at the corners outside the parallelogram. To follow these steps, Michael can use any of the given dimensions to form such a rectangle.

Upon evaluating each of the dimensions, it turns out that all the given dimensions are suitable for drawing the rectangle around the parallelogram ABCD:

1. Rectangle with dimensions 2 units by 4 units:
- Area of the rectangle = [tex]\( 2 \times 4 = 8 \)[/tex] square units.

2. Rectangle with dimensions 3 units by 2 units:
- Area of the rectangle = [tex]\( 3 \times 2 = 6 \)[/tex] square units.

3. Rectangle with dimensions 4 units by 4 units:
- Area of the rectangle = [tex]\( 4 \times 4 = 16 \)[/tex] square units.

Thus, the suitable dimensions for drawing the rectangle around parallelogram ABCD are:
- (2 units by 4 units)
- (3 units by 2 units)
- (4 units by 4 units)

Hence, Michael can use any of these dimensions for step 1 in his method.