Information about the recycling drive at school is shown in the table. Let [tex]$A$[/tex] be the event that the item pulled out of the recycling bin is a plastic bottle, and let [tex]$B$[/tex] be the event that a tenth grader recycled that item.

\begin{tabular}{|c|c|c|c|c|}
\hline & \begin{tabular}{c}
Aluminum \\
Cans
\end{tabular} & \begin{tabular}{c}
Glass \\
Bottles
\end{tabular} & \begin{tabular}{c}
Plastic \\
Bottles
\end{tabular} & Total \\
\hline Tenth Grade & 80 & 30 & 40 & 150 \\
\hline Eleventh Grade & 56 & 9 & 45 & 110 \\
\hline Twelfth Grade & 64 & 26 & 50 & 140 \\
\hline Total & 200 & 65 & 135 & 400 \\
\hline
\end{tabular}

Which statement is true about whether [tex]$A$[/tex] and [tex]$B$[/tex] are independent events?

A. [tex]$A$[/tex] and [tex]$B$[/tex] are independent events because [tex]$P(A \mid B) = P(A)$[/tex].
B. [tex]$A$[/tex] and [tex]$B$[/tex] are independent events because [tex]$P(A \mid B) = P(B)$[/tex].
C. [tex]$A$[/tex] and [tex]$B$[/tex] are not independent events because [tex]$P(A \mid B) \neq P(A)$[/tex].
D. [tex]$A$[/tex] and [tex]$B$[/tex] are not independent events because [tex]$P(A \mid B) \neq P(B)$[/tex].



Answer :

To determine whether the events [tex]\(A\)[/tex] (selecting a plastic bottle) and [tex]\(B\)[/tex] (the item was recycled by a tenth grader) are independent, we need to check if [tex]\(P(A \mid B) = P(A)\)[/tex]. Here’s how we can proceed step by step:

### Step 1: Calculate [tex]\(P(A)\)[/tex]
[tex]\(P(A)\)[/tex] is the probability of selecting a plastic bottle from the entire set of recycled items.

From the table:
- Total number of recycled items [tex]\(= 400\)[/tex]
- Number of plastic bottles [tex]\(= 135\)[/tex]

[tex]\[P(A) = \frac{\text{Number of plastic bottles}}{\text{Total number of recycled items}} = \frac{135}{400}\][/tex]

### Step 2: Calculate [tex]\(P(A \mid B)\)[/tex]
[tex]\(P(A \mid B)\)[/tex] is the probability of selecting a plastic bottle given that it was recycled by a tenth grader.

From the table:
- Total number of items recycled by tenth graders [tex]\(= 150\)[/tex]
- Number of plastic bottles recycled by tenth graders [tex]\(= 40\)[/tex]

[tex]\[P(A \mid B) = \frac{\text{Number of plastic bottles recycled by tenth graders}}{\text{Total number of items recycled by tenth graders}} = \frac{40}{150}\][/tex]

### Step 3: Compare [tex]\(P(A)\)[/tex] and [tex]\(P(A \mid B)\)[/tex]
Now, we compare the two probabilities:

- [tex]\(P(A) = \frac{135}{400}\)[/tex]
- [tex]\(P(A \mid B) = \frac{40}{150}\)[/tex]

We notice from the given information that [tex]\(P(A) \neq P(A \mid B)\)[/tex].

### Conclusion
Since [tex]\(P(A) \neq P(A \mid B)\)[/tex], the events [tex]\(A\)[/tex] and [tex]\(B\)[/tex] are not independent. Therefore, the correct statement is:

[tex]$A$[/tex] and [tex]$B$[/tex] are not independent events because [tex]\(P(A \mid B) \neq P(A)\)[/tex].

So, the answer is:
[tex]\[ \text{A and B are not independent events because } P(A \mid B) \neq P(A). \][/tex]