Find the length of the legs of a [tex]$45^{\circ}-45^{\circ}-90^{\circ}$[/tex] triangle if the hypotenuse measures [tex]$7 \sqrt{2}$[/tex] units.



Answer :

Certainly! Let's analyze a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle, which is a special right triangle. In such a triangle, the sides have unique relationships with each other:

1. The two legs are congruent (i.e., they have the same length).
2. The hypotenuse is [tex]\( \sqrt{2} \)[/tex] times longer than each leg.

Given that the hypotenuse of the triangle measures [tex]\( 7\sqrt{2} \)[/tex] units, we want to find the lengths of the other two sides (the legs).

Here are the steps:

1. Identify the length of the hypotenuse:
[tex]\[ \text{Hypotenuse} = 7\sqrt{2} \text{ units} \][/tex]

2. Recall the relationship in a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle: the hypotenuse ([tex]\(c\)[/tex]) is [tex]\( \sqrt{2} \)[/tex] times the length of each leg ([tex]\(a\)[/tex]):
[tex]\[ c = a\sqrt{2} \][/tex]

3. Substitute the given hypotenuse length into the equation to solve for [tex]\(a\)[/tex]:
[tex]\[ 7\sqrt{2} = a \sqrt{2} \][/tex]

4. To find the length of each leg ([tex]\(a\)[/tex]), divide both sides of the equation by [tex]\( \sqrt{2} \)[/tex]:
[tex]\[ a = \frac{7\sqrt{2}}{\sqrt{2}} \][/tex]

5. Simplify the fraction:
[tex]\[ a = 7 \][/tex]

Therefore, the lengths of the legs of the triangle are each:
[tex]\[ \text{Side length} = 7 \text{ units} \][/tex]

Given our numerical results, we see that the hypotenuse is [tex]\( 9.899494936611665 \)[/tex] and each leg is [tex]\( 7 \)[/tex] units (more precisely [tex]\(6.999999999999999\)[/tex] due to rounding errors in computational results).

Thus, for practical purposes, each leg is approximately:
[tex]\[ 7 \text{ units} \][/tex]