## Answer :

27=3x-5+x

27+5=4x-5+5

4x=32

4x/4=32/4

x=8

There are 8 blue marbles and 19 red marbles.

27+5=4x-5+5

4x=32

4x/4=32/4

x=8

There are 8 blue marbles and 19 red marbles.

Let

x--------> The number of red marbles

y--------> The number of blue marbles

we know that

[tex] x+y=27\\ x=27-y [/tex]

**equation [tex] 1 [/tex]**

[tex] x=3y-5 [/tex]

**equation [tex] 2 [/tex]**

**equate equation [tex] 1 [/tex] and equation [tex] 2 [/tex]**

[tex] 27-y=3y-5\\ 3y+y=27+5\\ 4y=32\\ y=8 [/tex]

[tex] x=3*8-5\\ x=19 [/tex]

therefore

**the answer is**

**The number of red marbles is [tex] 19 [/tex]**

**The number of blue marbles is [tex] 8 [/tex]**