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Robert is a 15-year-old boy. His recommended dietary intake for vitamin B12, C, and E is [tex]$2.4 \mu g/$[/tex] day, [tex]$75 mg/$[/tex] day, and [tex]$15 mg/$[/tex] day, respectively. He eats a salmon fillet with one cup of boiled green beans and half a cup of fresh sliced strawberries for lunch. If the nutrient values of his meal components are as shown below, for which vitamins did Robert meet at least [tex]$75 \%$[/tex] of his recommended daily allowance?

\begin{tabular}{|l|l|l|l|}
\hline
& Vitamin B12 & Vitamin C & Vitamin E \\
\hline
salmon fillet (124 g) & [tex]$5.87 \mu g$[/tex] & 0.0 mg & 0.60 mg \\
\hline
boiled green beans (1 cup) & [tex]$0.0 \mu g$[/tex] & 12.1 mg & 0.57 mg \\
\hline
strawberries, sliced (1/2 cup) & [tex]$0.0 \mu g$[/tex] & 49.0 mg & 0.42 mg \\
\hline
\end{tabular}

A. Vitamin B12, Vitamin C, and Vitamin E

B. Vitamin B12 and Vitamin C only

C. Vitamin B12 and Vitamin E only

D. Vitamin C and Vitamin E only

E. Vitamin B12 only



Answer :

GinnyAnswer
To determine for which vitamins Robert met at least 75% of his recommended daily allowance (RDA), we need to:

1. Calculate the total intake of each vitamin from his meal.
2. Calculate the percentage of the RDA each total intake represents.
3. Check if the percentage is at least 75%.

Given the nutrient values in his meal:

- Salmon fillet (124 g)
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg\)[/tex]

- Boiled green beans (1 cup)
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg\)[/tex]
- Vitamin E: [tex]\(0.57 mg\)[/tex]

- Strawberries, sliced (1/2 cup)
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 mg\)[/tex]
- Vitamin E: [tex]\(0.42 mg\)[/tex]

### Step 1: Total Intake

Total Vitamin B12 intake:
[tex]\[ 5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g \][/tex]

Total Vitamin C intake:
[tex]\[ 0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg \][/tex]

Total Vitamin E intake:
[tex]\[ 0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg \][/tex]

### Step 2: Percentage of RDA

Vitamin B12:
RDA = [tex]\(2.4 \mu g\)[/tex]

[tex]\[ \left( \frac{5.87 \mu g}{2.4 \mu g} \right) \times 100 \approx 244.58\% \][/tex]

Vitamin C:
RDA = [tex]\(75 mg\)[/tex]

[tex]\[ \left( \frac{61.1 mg}{75 mg} \right) \times 100 \approx 81.47\% \][/tex]

Vitamin E:
RDA = [tex]\(15 mg\)[/tex]

[tex]\[ \left( \frac{1.59 mg}{15 mg} \right) \times 100 \approx 10.6\% \][/tex]

### Step 3: Check if percentage ≥ 75%

- For Vitamin B12, the percentage is approximately 244.58%, which is greater than 75%.
- For Vitamin C, the percentage is approximately 81.47%, which is greater than 75%.
- For Vitamin E, the percentage is approximately 10.6%, which is less than 75%.

Thus, Robert met at least 75% of his RDA for Vitamin B12 and Vitamin C.

The correct answer is:
[tex]\[ \boxed{\text{B}} \][/tex]

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