What is the recursive formula when given the explicit formula for the following geometric sequence?

[tex]\[ a_n=12(33)^{n-1} \][/tex]

A. [tex]\( a_1=12, \, a_n=33 \, a_{n-1} \)[/tex]

B. [tex]\( a_1=12, \, a_n=-33 \, a_{n-1} \)[/tex]

C. [tex]\( a_1=33, \, a_n=-12 \, a_{n-1} \)[/tex]

D. [tex]\( a_1=33, \, a_n=12 \, a_{n-1} \)[/tex]



Answer :

Sure, let's answer the question by finding a detailed, step-by-step solution.

We start with the given explicit formula for the geometric sequence:
[tex]\[ a_n = 12 \cdot (33)^{n-1} \][/tex]

A geometric sequence is a sequence of numbers in which each term after the first is found by multiplying the previous term by a constant called the common ratio. To convert the explicit formula into a recursive formula, we first need to identify the first term and the common ratio.

1. Identify the first term:

The first term, [tex]\( a_1 \)[/tex], is found by setting [tex]\( n = 1 \)[/tex]:
[tex]\[ a_1 = 12 \cdot (33)^{1-1} = 12 \cdot (33)^0 = 12 \cdot 1 = 12 \][/tex]
So, [tex]\( a_1 = 12 \)[/tex].

2. Identify the common ratio:

In the explicit formula, the common ratio [tex]\( r \)[/tex] is the base of the exponent with [tex]\( n-1 \)[/tex], which in this case is 33. Therefore:
[tex]\[ r = 33 \][/tex]

3. Write the recursive formula:

In a recursive formula for a geometric sequence, you express each term in terms of the previous term multiplied by the common ratio. The general form is:
[tex]\[ a_n = r \cdot a_{n-1} \][/tex]
So, for our sequence, we substitute [tex]\( r \)[/tex] with 33:
[tex]\[ a_n = 33 \cdot a_{n-1} \][/tex]

4. Combine with the initial term:

We already know that the first term [tex]\( a_1 = 12 \)[/tex]. Therefore, the recursive formula becomes:
[tex]\[ a_1 = 12 \][/tex]
[tex]\[ a_n = 33 \cdot a_{n-1} \quad \text{for} \quad n > 1 \][/tex]

Thus, the recursive formula matching the given explicit formula is:
[tex]\[ a_1 = 12, \quad a_n = 33 \cdot a_{n-1} \][/tex]

Therefore, the correct option is:

A. [tex]\( a_1 = 12, \quad a_n = 33 \cdot a_{n-1} \)[/tex]