Determine the limit of the sequence or state that the sequence diverges.

[tex]\[ a_n = 6 - \frac{3}{n^2} \][/tex]

(Use symbolic notation and fractions where needed. Enter DNE if the sequence diverges.)

[tex]\[ \lim_{n \rightarrow \infty} a_n = ? \][/tex]



Answer :

Let's determine the limit of the sequence [tex]\( a_n = 6 - \frac{3}{n^2} \)[/tex] as [tex]\( n \)[/tex] approaches infinity.

1. We start by examining the given sequence:
[tex]\[ a_n = 6 - \frac{3}{n^2} \][/tex]

2. To find the limit as [tex]\( n \)[/tex] approaches infinity, we analyze each term separately:

- The term [tex]\( 6 \)[/tex] remains constant as [tex]\( n \)[/tex] approaches infinity.

- The term [tex]\( \frac{3}{n^2} \)[/tex] changes as [tex]\( n \)[/tex] grows larger. Since [tex]\( n^2 \)[/tex] becomes very large as [tex]\( n \)[/tex] approaches infinity, [tex]\( \frac{3}{n^2} \)[/tex] becomes very small.

3. Formally, as [tex]\( n \)[/tex] approaches infinity, [tex]\( n^2 \rightarrow \infty \)[/tex].

4. Hence, [tex]\( \frac{3}{n^2} \rightarrow 0 \)[/tex].

5. Therefore, the sequence [tex]\( 6 - \frac{3}{n^2} \)[/tex] approaches:
[tex]\[ 6 - 0 = 6. \][/tex]

6. Thus, we conclude that the limit of the sequence [tex]\( a_n \)[/tex] as [tex]\( n \)[/tex] approaches infinity is:
[tex]\[ \lim_{n \rightarrow \infty} a_n = 6 \][/tex]

So, the limit of [tex]\( a_n \)[/tex] is [tex]\(\boxed{6}\)[/tex]. The initial value given in the problem ([tex]\( \lim_{n \rightarrow \infty} a_n = 1 \)[/tex]) appears to be incorrect based on the analysis.