Harita must memorize 90 measures of music for her cello solo at a concert. She plans on memorizing 18 new measures for every 3 days of practice. Which equation can be used to determine [tex]$m$[/tex], the number of measures Harita still needs to memorize, as a function of [tex]$d$[/tex], the number of days of practice since she began learning the piece?

A. [tex]$m = 72 - 15d$[/tex]
B. [tex][tex]$m = 90 - 6d$[/tex][/tex]
C. [tex]$m = 101 - 21d$[/tex]
D. [tex]$m = 108 - 3d$[/tex]



Answer :

To determine the equation that shows the number of measures [tex]\( m \)[/tex] Harita still needs to memorize as a function of [tex]\( d \)[/tex] days of practice:

1. Identify the total number of measures Harita needs to memorize: [tex]\( 90 \)[/tex] measures.

2. Identify the number of measures she memorizes over a set period: Harita memorizes [tex]\( 18 \)[/tex] measures every [tex]\( 3 \)[/tex] days.

3. Determine the number of measures memorized per day:
[tex]\[ \text{Measures per day} = \frac{\text{Measures per 3 days}}{3} = \frac{18}{3} = 6 \text{ measures per day} \][/tex]

4. Define the relationship between the number of days [tex]\( d \)[/tex] and the number of measures memorized:
If Harita memorizes [tex]\( 6 \)[/tex] measures per day, then after [tex]\( d \)[/tex] days, she will have memorized [tex]\( 6d \)[/tex] measures.

5. Formulate the equation for the number of measures left to memorize:
Harita started with [tex]\( 90 \)[/tex] measures, and she reduces this by the number of measures she has memorized after [tex]\( d \)[/tex] days:
[tex]\[ m = 90 - 6d \][/tex]
Here,
- [tex]\( 90 \)[/tex] is the initial total number of measures.
- [tex]\( 6d \)[/tex] is the number of measures she has memorized after [tex]\( d \)[/tex] days.

6. Verify the options provided:
- [tex]\( m = 72 - 15d \)[/tex]
- [tex]\( m = 90 - 6d \)[/tex]
- [tex]\( m = 101 - 21d \)[/tex]
- [tex]\( m = 108 - 3d \)[/tex]

The correct equation that represents the number of measures Harita still needs to memorize, given she memorizes 6 measures per day, is:
[tex]\[ m = 90 - 6d \][/tex]