Drag each set of coordinates to the correct location on the table. Not all sets of coordinates will be used.

Points that two lines pass through are given in the table. Match each point of intersection to the correct pair of lines.

\begin{tabular}{|l|l|l|}
\hline
Line 1 & Line 2 & Point of Intersection \\
\hline
[tex]$(2,5),(-3,-5)$[/tex] & [tex]$(3,0),(0,-3)$[/tex] & \\
\hline
[tex]$(1,1),(2,3)$[/tex] & [tex]$(0,3),(2,5)$[/tex] & \\
\hline
[tex]$(1,0),(0,-1)$[/tex] & [tex]$(0,3),(-2,-1)$[/tex] & \\
\hline
\end{tabular}

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Answer :

To find the points of intersection, we need to determine where each pair of lines crosses.

Let's first consider each pair of lines and calculate the point of intersection for each.

1. Lines through (2, 5) and (-3, -5), and (3, 0) and (0, -3):
- These two lines intersect at the point (4.0, 7.0).

2. Lines through (1, 1) and (2, 3), and (0, 3) and (2, 5):
- These two lines intersect at the point (-4.0, -7.0).

3. Lines through (1, 0) and (0, -1), and (0, 3) and (-2, -1):
- These two lines intersect at the point (4.0, 5.0).

So, the correct points of intersection for the given pairs of lines are:

\begin{tabular}{|l|l|l|}
\hline Line 1 & Line 2 & Point of Intersection \\
\hline [tex]$(2, 5), (-3, -5)$[/tex] & [tex]$(3, 0), (0, -3)$[/tex] & (4.0, 7.0) \\
\hline [tex]$(1, 1), (2, 3)$[/tex] & [tex]$(0, 3), (2, 5)$[/tex] & (-4.0, -7.0) \\
\hline [tex]$(1, 0), (0, -1)$[/tex] & [tex]$(0, 3), (-2, -1)$[/tex] & (4.0, 5.0) \\
\hline
\end{tabular}