To determine which reactions will occur based on the activity series [tex]\(F > Cl > Br > I\)[/tex], we need to compare the reactivity of the halogens in each pair of reactants.
1. First reaction: [tex]\(CuI_2 + Br_2\)[/tex]
- Iodine (I) is less reactive than Bromine (Br).
- In the activity series, Bromine (Br) is more reactive than Iodine (I).
- Therefore, Bromine can replace Iodine in the compound [tex]\(CuI_2\)[/tex].
This reaction will occur.
2. Second reaction: [tex]\(Cl_2 + AlF_3\)[/tex]
- Chlorine (Cl) is less reactive than Fluorine (F).
- In the activity series, Fluorine (F) is more reactive than Chlorine (Cl).
- As a result, Chlorine will not be able to replace Fluorine in [tex]\(AlF_3\)[/tex].
This reaction will not occur.
3. Third reaction: [tex]\(Br_2 + NaCl\)[/tex]
- Bromine (Br) is less reactive than Chlorine (Cl).
- In the activity series, Chlorine (Cl) is more reactive than Bromine (Br).
- Therefore, Bromine cannot replace Chlorine in [tex]\(NaCl\)[/tex].
This reaction will not occur.
4. Fourth reaction: [tex]\(CuF_2 + I_2\)[/tex]
- Iodine (I) is less reactive than Fluorine (F).
- In the activity series, Fluorine (F) is more reactive than Iodine (I).
- Hence, Iodine cannot replace Fluorine in [tex]\(CuF_2\)[/tex].
This reaction will not occur.
Summarizing the results:
- The reaction [tex]\(CuI_2 + Br_2\)[/tex] will occur.
- The reaction [tex]\(Cl_2 + AlF_3\)[/tex] will not occur.
- The reaction [tex]\(Br_2 + NaCl\)[/tex] will not occur.
- The reaction [tex]\(CuF_2 + I_2\)[/tex] will not occur.
Thus, the outcomes are:
- Reaction 1: True (will occur)
- Reaction 2: False (will not occur)
- Reaction 3: False (will not occur)
- Reaction 4: False (will not occur)
The answer is [tex]\((True, False, False, False)\)[/tex].
