To predict the products of the decomposition reaction for [tex]\(2 \text{LiClO}_3\)[/tex], let's observe the provided reactions and look for patterns:
1. [tex]\(2 \text{NaClO}_3 \rightarrow 2 \text{NaCl} + 3 \text{O}_2\)[/tex]
2. [tex]\(2 \text{KClO}_3 \rightarrow 3 \text{O}_2 + 2 \text{KCl}\)[/tex]
In both examples, the decomposition of the compound follows a pattern where:
- The [tex]\(\text{ClO}_3\)[/tex] splits into [tex]\(\text{Cl}\)[/tex] and [tex]\(\text{O}_2\)[/tex].
- Each decomposition produces 2 moles of the corresponding chloride ([tex]\(\text{NaCl}\)[/tex] or [tex]\(\text{KCl}\)[/tex]).
- Each decomposition also produces 3 moles of [tex]\(\text{O}_2\)[/tex].
Based on the patterns observed:
1. The coefficients [tex]\(2\)[/tex] for [tex]\(\text{NaClO}_3\)[/tex] and [tex]\(\text{KClO}_3\)[/tex] remain consistent before and after the reaction.
2. The products always consist of 2 moles of the metal chloride and 3 moles of [tex]\(\text{O}_2\)[/tex].
Applying this pattern to [tex]\(2 \text{LiClO}_3\)[/tex]:
- The decomposition would produce 2 moles of lithium chloride ([tex]\(\text{LiCl}\)[/tex]).
- The decomposition would also produce 3 moles of oxygen gas ([tex]\(\text{O}_2\)[/tex]).
Thus, the expected products of the decomposition reaction of [tex]\(2 \text{LiClO}_3\)[/tex] are:
[tex]\[2 \text{LiCl} + 3 \text{O}_2\][/tex]
So, Rosa should record the following in the last row of the table:
[tex]\[2 \text{LiCl} + 3 \text{O}_2\][/tex]
This matches the first option provided. Therefore, the correct answer is:
[tex]\[2 \text{LiCl} + 3 \text{O}_2\][/tex]
