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Based on what you've read, answer the following questions.

1. Determine whether or not the equation below is balanced. If it isn't balanced, write the balanced form. Also, identify the reactant(s) and product(s) in this equation. Finally, label this as one of the five types of reactions: combination, decomposition, single replacement, double replacement, or reversible.

[tex] \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 [/tex]



Answer :

GinnyAnswer
Sure, let's address the provided reaction step by step.

### Step 1: Identify Reactants and Products

The given chemical equation is:
[tex]\[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]

- Reactants: Zn (Zinc) and HCl (Hydrochloric acid)
- Products: ZnCl[tex]\(_2\)[/tex] (Zinc chloride) and H[tex]\(_2\)[/tex] (Hydrogen gas)

### Step 2: Determine if the Equation is Balanced

To determine if the equation is balanced, count the number of atoms of each element on both sides of the equation.

#### Reactant Side:
- Zn: 1 atom
- H: 1 atom (from HCl)
- Cl: 1 atom (from HCl)

#### Product Side:
- Zn: 1 atom
- H: 2 atoms (from H[tex]\(_2\)[/tex])
- Cl: 2 atoms (from ZnCl[tex]\(_2\)[/tex])

Clearly, the number of hydrogen (H) and chlorine (Cl) atoms on the reactant side does not match the number of those on the product side. Therefore, the equation is not balanced.

### Step 3: Balance the Equation

To balance the equation, adjust the coefficients (the numbers in front of substances) so that the number of atoms of each element is the same on both sides.

#### Balancing Process:

1. Start with hydrogen (H) and chlorine (Cl):
- On the product side, we have 2 atoms of H and 2 atoms of Cl in ZnCl[tex]\(_2\)[/tex] and H[tex]\(_2\)[/tex] respectively.
- On the reactant side, we currently have only 1 atom of H and 1 atom of Cl in HCl.
2. To balance H and Cl, place a coefficient of 2 in front of HCl:
[tex]\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]

Now, count the atoms on both sides:

#### Reactant Side (After Balancing):
- Zn: 1 atom
- H: 2 atoms (from 2 HCl)
- Cl: 2 atoms (from 2 HCl)

#### Product Side:
- Zn: 1 atom
- H: 2 atoms (from H[tex]\(_2\)[/tex])
- Cl: 2 atoms (from ZnCl[tex]\(_2\)[/tex])

Now, each element has the same number of atoms on both the reactant and product sides. The equation is balanced.

### Final Balanced Equation:
[tex]\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]

### Step 4: Identify the Type of Reaction

This reaction is a single replacement reaction because Zinc (Zn) replaces the hydrogen (H) in hydrochloric acid (HCl), forming zinc chloride (ZnCl[tex]\(_2\)[/tex]) and hydrogen gas (H[tex]\(_2\)[/tex]).

### Summary
- Reactants: Zn, HCl
- Products: ZnCl[tex]\(_2\)[/tex], H[tex]\(_2\)[/tex]
- Balanced Equation: [tex]\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]
- Type of Reaction: Single replacement reaction

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