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Use the table to answer the questions below.

When the temperature in a room increases from [tex]25^{\circ} C[/tex] to [tex]33^{\circ} C[/tex], [tex]\square[/tex] changes from a solid to a liquid.

\begin{tabular}{|r|r|r|}
\hline
\multicolumn{1}{|c|}{Substance} & \begin{tabular}{c} Melting \\ point [tex]$\left({}^{\circ} C \right)$[/tex] \end{tabular} & \begin{tabular}{c} Boiling \\ point [tex]$\left({}^{\circ} C \right)$[/tex] \end{tabular} \\
\hline
Gallium [tex]$(Ga)$[/tex] & 30 & 2,204 \\
\hline
Gold [tex]$(Au)$[/tex] & 1,064 & 2,856 \\
\hline
Methane [tex]$\left(CH_4\right)$[/tex] & -183 & -162 \\
\hline
Nitrogen [tex]$\left(N_2\right)$[/tex] & -210 & -196 \\
\hline
\end{tabular}

In a lab, methane and nitrogen are cooled from [tex]-170^{\circ} C[/tex] to [tex]-200^{\circ} C[/tex]. The methane freezes and the nitrogen [tex]\square[/tex].

When gold is heated to [tex]2,856^{\circ} C[/tex], it changes from a liquid to a [tex]\square[/tex].



Answer :

GinnyAnswer
To answer the questions, let's analyze the data in the table and the given temperature changes in detail.

### First Scenario: Room Temperature Increases from [tex]\( 25^{\circ} C \)[/tex] to [tex]\( 33^{\circ} C \)[/tex]

We need to determine which substance changes from a solid to a liquid as the temperature in the room increases from [tex]\( 25^{\circ} C \)[/tex] to [tex]\( 33^{\circ} C \)[/tex].

From the given table:
- Gallium (Ga) has a melting point of [tex]\( 30^{\circ} C \)[/tex].
- Gold (Au) has a melting point of [tex]\( 1064^{\circ} C \)[/tex].
- Methane (CH[tex]\(_4\)[/tex]) has a melting point of [tex]\( -183^{\circ} C \)[/tex].
- Nitrogen (N[tex]\(_2\)[/tex]) has a melting point of [tex]\( -210^{\circ} C \)[/tex].

In the range of [tex]\( 25^{\circ} C \)[/tex] to [tex]\( 33^{\circ} C \)[/tex]:
- Gallium (Ga) has a melting point of [tex]\( 30^{\circ} C \)[/tex], which falls within this range. Therefore, Gallium changes from a solid to a liquid.

Thus, the answer is:
When the temperature in a room increases from [tex]\( 25^{\circ} C \)[/tex] to [tex]\( 33^{\circ} C \)[/tex], Gallium (Ga) changes from a solid to a liquid.

### Second Scenario: Methane and Nitrogen Cooled from [tex]\( -170^{\circ} C \)[/tex] to [tex]\( -200^{\circ} C \)[/tex]

We need to determine the state changes of methane and nitrogen when cooled from [tex]\( -170^{\circ} C \)[/tex] to [tex]\( -200^{\circ} C \)[/tex].

From the given table:
- Methane (CH[tex]\(_4\)[/tex]) has a melting point of [tex]\( -183^{\circ} C \)[/tex] and a boiling point of [tex]\( -162^{\circ} C \)[/tex]. At [tex]\( -170^{\circ} C \)[/tex], methane is in gas form (above its boiling point [tex]\( -162^{\circ} C \)[/tex]). When cooled below [tex]\( -183^{\circ} C \)[/tex], it freezes.
- Nitrogen (N[tex]\(_2\)[/tex]) has a melting point of [tex]\( -210^{\circ} C \)[/tex] and a boiling point of [tex]\( -196^{\circ} C \)[/tex]. At [tex]\( -170^{\circ} C \)[/tex], nitrogen is in liquid form. When cooled below [tex]\( -196^{\circ} C \)[/tex], it condenses to liquid if it is in gas form (if cooled further below [tex]\( -210^{\circ} C \)[/tex] would freeze).

Thus, the answer is:
When methane and nitrogen are cooled from [tex]\( -170^{\circ} C \)[/tex] to [tex]\( -200^{\circ} C \)[/tex], the methane freezes and the nitrogen condenses.

### Third Scenario: Gold Heated to [tex]\( 2856^{\circ} C \)[/tex]

We need to determine the state change of gold when heated to [tex]\( 2856^{\circ} C \)[/tex].

From the given table:
- Gold (Au) has a boiling point of [tex]\( 2856^{\circ} C \)[/tex].

When gold reaches its boiling point temperature of [tex]\( 2856^{\circ} C \)[/tex], it changes from a liquid to a gas.

Thus, the answer is:
When gold is heated to [tex]\( 2856^{\circ} C \)[/tex], it changes from a liquid to a gas.

Combining all the answers together, we have:
```
('Gallium (Ga)', 'freezes', 'condenses', 'gas')
```

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