Enter the explicit rule for the geometric sequence.

[tex]\[
\begin{array}{l}
60, 12, \frac{12}{5}, \frac{12}{25}, \frac{12}{125}, \ldots \\
a_n = \square
\end{array}
\][/tex]



Answer :

To determine the explicit rule for the given geometric sequence:

[tex]\[ 60, 12, \frac{12}{5}, \frac{12}{25}, \frac{12}{125}, \ldots \][/tex]

let's follow these steps:

1. Identify the first term ([tex]\(a_1\)[/tex]):
The first term of the sequence is [tex]\(a_1 = 60\)[/tex].

2. Determine the common ratio ([tex]\(r\)[/tex]):
The common ratio [tex]\(r\)[/tex] can be found by dividing any term by its preceding term.

[tex]\[ r = \frac{12}{60} = 0.2 \][/tex]

3. Use the explicit formula for the [tex]\(n\)[/tex]-th term of a geometric sequence:
The formula for the [tex]\(n\)[/tex]-th term is given by:
[tex]\[ a_n = a_1 \cdot r^{(n-1)} \][/tex]
where:
- [tex]\(a_1\)[/tex] is the first term.
- [tex]\(r\)[/tex] is the common ratio.
- [tex]\(n\)[/tex] is the term number.

Plugging in the values we have:
- [tex]\(a_1 = 60\)[/tex]
- [tex]\(r = 0.2\)[/tex]

The explicit rule for the [tex]\(n\)[/tex]-th term of this geometric sequence is:

[tex]\[ a_n = 60 \cdot (0.2)^{(n-1)} \][/tex]