A raindrop has a mass of 50 mg and the Pacific Ocean has a mass of [tex]$7.08 \times 10^{20} \text{ kg}$[/tex].

Use this information to answer the question below. Be sure your answers have the correct number of significant digits.

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What is the mass of 1 mole of raindrops? \\
Round your answer to 2 significant digits. & \\
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Answer :

To determine the mass of 1 mole of raindrops, follow these steps:

1. Determine the mass of one raindrop in grams:
Given the mass of one raindrop is 50 milligrams (mg), we need to convert this to grams (g). There are 1000 milligrams in a gram.

[tex]\[ \text{mass of one raindrop in grams} = 50 \, \text{mg} \times \left( \frac{1 \, \text{g}}{1000 \, \text{mg}} \right) = 0.050 \, \text{g} \][/tex]

2. Use Avogadro's number to find the mass of 1 mole of raindrops:
Avogadro's number is [tex]\(6.022 \times 10^{23}\)[/tex], which is the number of particles (in this case, raindrops) in 1 mole.

[tex]\[ \text{mass of 1 mole of raindrops} = 0.050 \, \text{g} \times 6.022 \times 10^{23} \][/tex]

3. Calculate the result:
Performing the multiplication,

[tex]\[ \text{mass of 1 mole of raindrops} = 0.050 \, \text{g} \times 6.022 \times 10^{23} = 3.011 \times 10^{22} \, \text{g} \][/tex]

4. Round the answer to 2 significant digits:
The result in scientific notation is already in the correct form. Rounding the answer to 2 significant digits, we get:

[tex]\[ \text{mass of 1 mole of raindrops} \approx 3.0 \times 10^{22} \, \text{g} \][/tex]

Thus, the mass of 1 mole of raindrops is approximately [tex]\(3.0 \times 10^{22} \, \text{g}\)[/tex].