Answer :
To write the equation of a line in slope-intercept form, we use the general formula:
[tex]\[ y = mx + b \][/tex]
where:
- [tex]\( m \)[/tex] is the slope of the line.
- [tex]\( b \)[/tex] is the y-intercept of the line. This is the point where the line crosses the y-axis.
Given the problem:
- The slope [tex]\( m \)[/tex] is [tex]\( \frac{1}{4} \)[/tex].
- The y-intercept [tex]\( b \)[/tex] is [tex]\(-2\)[/tex].
Substitute these values into the slope-intercept form equation:
[tex]\[ y = \frac{1}{4}x + (-2) \][/tex]
or, simplifying the expression:
[tex]\[ y = 0.25x - 2 \][/tex]
Thus, the equation of the line in slope-intercept form is:
[tex]\[ y = 0.25x - 2 \][/tex]
[tex]\[ y = mx + b \][/tex]
where:
- [tex]\( m \)[/tex] is the slope of the line.
- [tex]\( b \)[/tex] is the y-intercept of the line. This is the point where the line crosses the y-axis.
Given the problem:
- The slope [tex]\( m \)[/tex] is [tex]\( \frac{1}{4} \)[/tex].
- The y-intercept [tex]\( b \)[/tex] is [tex]\(-2\)[/tex].
Substitute these values into the slope-intercept form equation:
[tex]\[ y = \frac{1}{4}x + (-2) \][/tex]
or, simplifying the expression:
[tex]\[ y = 0.25x - 2 \][/tex]
Thus, the equation of the line in slope-intercept form is:
[tex]\[ y = 0.25x - 2 \][/tex]