Answer :
Answer:
There are 10 3-point questions, and 14 5-point questions.
Step-by-step explanation:
System of Equations
When presented with two or more equations, all with the same set of variables, the values of each of them can be calculated by using either the
- substitution method
(rearrange and plug an equation into another)
- elimination method
(multiply an equation by a factor and subtract it from another equation to eliminate a variable).
[tex]\hrulefill[/tex]
Solving the Problem
We're given the equations
[tex]x+y=24[/tex]
and
[tex]3x+5y=100[/tex].
Substitution Method
We can rearrange the first equation to have x in terms of y and plug it into the second equation!
[tex]x=24-y[/tex]
[tex]3(24-y)+5y=100[/tex]
[tex]72-3y+5y=100[/tex]
[tex]72+2y=100[/tex]
[tex]2y=28[/tex]
[tex]\boxed{y=14} \rightarrow \boxed{x = 10}[/tex]
[tex]\dotfill[/tex]
Elimination Method (Quicker)
We can multiply the first equation by 3 (or 5) and subtract it from the second.
[tex]3(x+y=24)\rightarrow 3x+3y=72[/tex]
[tex]\:\:\:\:\:\:3x + 5y &= 100 \\-(3x + 3y &= 72) \\[/tex]
[tex]2y=28[/tex]
[tex]\boxed{y=14}\rightarrow\boxed{x=10}[/tex]