Sure! Let's find the value of [tex]\( f(-3) \)[/tex] for the function [tex]\( f(x) = 2x^2 - 3x + 1 \)[/tex].
1. Substitute [tex]\( x = -3 \)[/tex] into the function:
[tex]\[
f(-3) = 2(-3)^2 - 3(-3) + 1
\][/tex]
2. Calculate [tex]\( (-3)^2 \)[/tex]:
[tex]\[
(-3)^2 = 9
\][/tex]
3. Multiply by 2:
[tex]\[
2 \times 9 = 18
\][/tex]
4. Calculate [tex]\( -3 \times (-3) \)[/tex]:
[tex]\[
-3 \times (-3) = 9
\][/tex]
5. Add all the terms together:
[tex]\[
18 + 9 + 1 = 28
\][/tex]
So, the value of [tex]\( f(-3) \)[/tex] is [tex]\( 28 \)[/tex].
