The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches. What is the height of the triangular base of the pyramid?

A. [tex]\(9 \sqrt{2}\)[/tex] in.
B. [tex]\(9 \sqrt{3}\)[/tex] in.
C. [tex]\(18 \sqrt{2}\)[/tex] in.
D. [tex]\(18 \sqrt{3}\)[/tex] in.



Answer :

Let's solve the problem step-by-step:

1. Identify the properties of an equilateral triangle: An equilateral triangle has all three sides of equal length and all interior angles of equal measure (60 degrees each).

2. Given information:
- The side length of the equilateral triangle is 18 inches.

3. Formula to find the height of an equilateral triangle:
- The height [tex]\( h \)[/tex] of an equilateral triangle can be determined using the formula:
[tex]\[ h = \frac{\sqrt{3}}{2} \times \text{side length} \][/tex]

4. Substitute the given side length into the formula:
- Here, the side length is 18 inches:
[tex]\[ h = \frac{\sqrt{3}}{2} \times 18 \][/tex]

5. Simplify the expression:
- First, multiply the fraction:
[tex]\[ h = \frac{\sqrt{3} \times 18}{2} \][/tex]
- Then, perform the multiplication:
[tex]\[ h = 9\sqrt{3} \][/tex]

So, the height of the triangular base of the pyramid is [tex]\(\boxed{9\sqrt{3} \text{ inches}}\)[/tex].