A kicker for a football team makes field goals [tex]$85 \%$[/tex] of the time when kicking from the 20-yard line. Assume that field goal attempts can be considered random events. Using the table, what is the probability that the placekicker will make at least 4 of his next 5 attempts from the 20-yard line?

\begin{tabular}{|c|c|c|c|c|c|c|}
\hline Field Goal & 0 & 1 & 2 & 3 & 4 & 5 \\
\hline Probability & 0.00008 & 0.002 & 0.024 & 0.138 & 0.392 & ? \\
\hline
\end{tabular}

A. 0.392

B. 0.444

C. 0.556

D. 0.836



Answer :

To calculate the probability that the placekicker will make at least 4 out of his next 5 field goal attempts from the 20-yard line, we need to consider two cases:

1. The probability of making exactly 4 out of 5 field goals.
2. The probability of making all 5 out of 5 field goals.

The given table provides the probabilities for making exactly 0, 1, 2, 3, 4, or 5 field goals out of 5 attempts. We need to specifically focus on the probabilities for 4 and 5 successful attempts.

From the table:
- The probability of making exactly 4 out of 5 field goals is 0.392.
- The probability of making exactly 5 out of 5 field goals is 0.444.

To find the total probability of making at least 4 out of 5 field goals, we need to sum these two probabilities:

[tex]\[ P(\text{at least 4 out of 5}) = P(\text{exactly 4 out of 5}) + P(\text{exactly 5 out of 5}) \][/tex]

Substituting the values from the table, we get:

[tex]\[ P(\text{at least 4 out of 5}) = 0.392 + 0.444 = 0.836 \][/tex]

Therefore, the probability that the placekicker will make at least 4 of his next 5 attempts from the 20-yard line is:

[tex]\[ \boxed{0.836} \][/tex]