Some of the steps in the derivation of the quadratic formula are shown.

Step 4: [tex]\frac{-4ac + b^2}{4a} = \alpha\left(x + \frac{b}{2a}\right)^2[/tex]

Step 5: [tex]\left(\frac{1}{a}\right) \frac{b^2 - 4ac}{4a} = \left(\frac{1}{a}\right) d\left(x + \frac{b}{2a}\right)^2[/tex]

Step 6: [tex]\frac{b^2 - 4ac}{4a^2} = \left(x + \frac{b}{2a}\right)^2[/tex]

Step 7: [tex]\frac{\pm \sqrt{b^2 - 4ac}}{2a} = x + \frac{b}{2a}[/tex]

Which best explains why the expression [tex]\pm \sqrt{b^2 - 4ac}[/tex] cannot be rewritten as [tex]D \pm \sqrt{-4ac}[/tex] during the next step?

A. Negative values, like -4ac, do not have a square root.
B. The [tex]\pm[/tex] symbol prevents the square root from being evaluated.
C. The square root of terms separated by addition and subtraction cannot be calculated individually.
D. The entire term [tex]b^2 - 4ac[/tex] must be divided by [tex]2a[/tex] before its square root can be determined.



Answer :

The best explanation for why the expression [tex]\( \pm \sqrt{b^2 - 4ac} \)[/tex] cannot be rewritten as [tex]\( D \pm \sqrt{-4ac} \)[/tex] during the step after Step 7 is:

The square root of terms separated by addition and subtraction cannot be calculated individually.

Here's a detailed, step-by-step breakdown:

1. Step 6 Simplification:
[tex]\[ \frac{b^2 - 4ac}{4a^2} = \left(x + \frac{b}{2a}\right)^2 \][/tex]
This step ensures that the quadratic expression is simplified into a perfect square on one side and a fraction on the other side.

2. Step 7 Square Root:
[tex]\[ \sqrt{\frac{b^2 - 4ac}{4a^2}} = \sqrt{\left(x + \frac{b}{2a}\right)^2} \][/tex]
Taking the square root of both sides, we get:
[tex]\[ \frac{\pm\sqrt{b^2 - 4ac}}{2a} = x + \frac{b}{2a} \][/tex]
Here, the entire expression within the square root on the left side is taken as a whole.

3. Understanding the Restriction:
In the given form ([tex]\(b^2 - 4ac\)[/tex]), separating and individually calculating the square roots of the terms ([tex]\(b^2\)[/tex] and [tex]\(-4ac\)[/tex]) before combining their results is not mathematically correct. This is because the square root operation distributes over multiplication and division but not addition and subtraction. Hence:
[tex]\[ \sqrt{b^2 - 4ac} \neq \sqrt{b^2} - \sqrt{4ac} \][/tex]

These steps explain why the original expression [tex]\( \pm \sqrt{b^2 - 4ac} \)[/tex] must remain whole and cannot be split into [tex]\( D \pm \sqrt{-4ac} \)[/tex]. Therefore, the correct explanation is that the square root of terms separated by addition and subtraction cannot be calculated individually.