What is the area of a triangle that has a base of 3 feet and a height of 6 feet?

A. [tex]$18 \text{ ft}^2$[/tex]
B. [tex]$9 \text{ ft}^2$[/tex]
C. [tex]$4.5 \text{ ft}^2$[/tex]
D. [tex]$18 \text{ ft}$[/tex]



Answer :

To determine the area of a triangle, you can use the formula:

[tex]\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \][/tex]

Given the base is 3 feet and the height is 6 feet, we can substitute these values into the formula:

[tex]\[ \text{Area} = \frac{1}{2} \times 3 \text{ feet} \times 6 \text{ feet} \][/tex]

First, multiply the base and the height:

[tex]\[ 3 \text{ feet} \times 6 \text{ feet} = 18 \text{ square feet} \][/tex]

Next, multiply by [tex]\(\frac{1}{2}\)[/tex]:

[tex]\[ \frac{1}{2} \times 18 \text{ square feet} = 9 \text{ square feet} \][/tex]

The area of the triangle is [tex]\(9 \text{ ft}^2\)[/tex].

So, the correct answer is:
[tex]\[ \boxed{9 \text{ ft}^2} \][/tex]