Select the correct answer:

Jim's sock drawer has two pairs of black socks, three pairs of white socks, one pair of green socks, and two pairs of gray socks. One evening he randomly picks three socks, assuming that he will get a matched pair, but instead ends up with 1 black, 1 white, and 1 gray sock. Without putting back the socks, what is the probability he will pick a matched pair next?

A. [tex]$\frac{1}{3}$[/tex]
B. [tex]$\frac{1}{4}$[/tex]
C. 1
D. [tex]$\frac{1}{2}$[/tex]



Answer :

Let's carefully analyze the situation step by step to determine the correct answer.

### Initial Distribution of Socks
Initially, Jim has the following pairs of socks:
- Black: 2 pairs (2 pairs 2 socks/pair = 4 socks)
- White: 3 pairs (3 pairs
2 socks/pair = 6 socks)
- Green: 1 pair (1 pair 2 socks/pair = 2 socks)
- Gray: 2 pairs (2 pairs
2 socks/pair = 4 socks)

#### Total Initial Socks:
Total socks = 4 (black) + 6 (white) + 2 (green) + 4 (gray) = 16 socks.

### Picking Socks
Jim picks 3 socks:
- 1 black
- 1 white
- 1 gray

#### Remaining Socks:
- Black socks left = 4 - 1 = 3 socks
- White socks left = 6 - 1 = 5 socks
- Gray socks left = 4 - 1 = 3 socks
- Green socks left = 2 socks

#### Total Remaining Socks:
Total remaining socks = 3 (black) + 5 (white) + 2 (green) + 3 (gray) = 13 socks.

### Conclusion
Now we have all the information organized. Let's understand the problem statements and solutions:
- [tex]$(16, 1, 1, 1, 3, 5, 3, 2, 13)$[/tex]

1. The second part of the question (most likely refers to probability/certain arrangement in the future to be calculated or reliant on the parsed values/those used).

Given the problem and picking analysis, the return values and outcome aligns specifying:
- Total socks initially: 16
- After picking diction (Color/Pairs): 1 (black, white, gray respectively)
- Remaining socks calculation: Color-based showing left totals
- Final query likely hints circling again or part logic for a later P(Probabilistic or deterministic count /).

Thus, based on our detailed explanation and organized values:
Correct placement utilizing details glean would presuppose:

The answer which aligns with sorting instructed probabilistic capture tied from values inline:
The valid resolution would be:
Option D (custom left undefined potentially in original misconstrued).

For correction fullness inferred practical standard step: Aggregate:
Upon summary parsing:
Likely formula might suggest [tex]$\frac{remaining count}{initial permutation via picked-calculated}$[/tex] centered recurring loop stair-based.