To determine the number of moles in 0.256 liters of a 0.855 M lithium nitrate solution, we can use the relationship given by molarity. The formula for molarity [tex]\( M \)[/tex] is:
[tex]\[
M = \frac{\text{moles}}{\text{liters}}
\][/tex]
We can rearrange this formula to solve for the number of moles:
[tex]\[
\text{moles} = M \times \text{liters}
\][/tex]
In this case, we know:
- The molarity [tex]\( M \)[/tex] of the solution is 0.855 M.
- The volume of the solution is 0.256 liters.
Plugging these values into the formula, we have:
[tex]\[
\text{moles} = 0.855 \, \text{M} \times 0.256 \, \text{L}
\][/tex]
By performing the multiplication:
[tex]\[
\text{moles} = 0.21888 \, \text{moles}
\][/tex]
So, the number of moles in 0.256 liters of a 0.855 M lithium nitrate solution is [tex]\( 0.21888 \)[/tex] moles.
