To determine the mass of BaSO₄ formed during the reaction, we can follow these steps:
1. Identify the moles of BaCl₂ reacted: From the earlier calculation, we know that 0.020 moles of BaCl₂ reacts.
2. Determine the stoichiometry of the reaction: The balanced chemical equation is:
[tex]\[ \text{BaCl}_2(\text{aq}) + \text{Na}_2\text{SO}_4(\text{aq}) \rightarrow \text{BaSO}_4(\text{s}) + 2 \text{NaCl}(\text{aq}) \][/tex]
According to this equation, the reaction occurs in a 1:1 mole ratio between BaCl₂ and BaSO₄. Thus, 0.020 moles of BaCl₂ will produce 0.020 moles of BaSO₄.
3. Calculate the mass of BaSO₄ formed:
- The molar mass of BaSO₄ is given as 233.39 g/mol.
- Using the formula for mass, [tex]\( \text{mass} = \text{moles} \times \text{molar mass} \)[/tex]
Therefore,
[tex]\[ \text{mass of BaSO}_4 = 0.020 \, \text{moles} \times 233.39 \, \text{g/mol} \][/tex]
[tex]\[ = 4.6678 \, \text{g} \][/tex]
So, the mass of BaSO₄ formed during the reaction is 4.6678 grams.
