3. Given that [tex]r=\binom{4a}{3}, q=\binom{5}{-4}[/tex] and [tex]r \cdot q=-2[/tex], find the value of [tex]a[/tex].

4. Two vectors [tex]y[/tex] and [tex]z[/tex] are given by [tex]\binom{3-x}{5x-2}[/tex] and [tex]\binom{-1}{-1}[/tex] respectively. If [tex]y \cdot z=-9[/tex], find the value of [tex]x[/tex].



Answer :

Let's solve the given problems step-by-step:

### Problem 3:
Given that [tex]\( r = \binom{4a}{3} \)[/tex], [tex]\( q = \binom{5}{-4} \)[/tex], and [tex]\( r \cdot q = -2 \)[/tex], we need to find the value of [tex]\( a \)[/tex].

1. Understanding the Binomial Coefficient [tex]\( q \)[/tex]:
[tex]\[ q = \binom{5}{-4} \][/tex]
The binomial coefficient [tex]\( \binom{n}{k} \)[/tex] is defined for non-negative integers [tex]\( n \)[/tex] and [tex]\( k \)[/tex]. If [tex]\( k \)[/tex] is negative, the binomial coefficient is zero:
[tex]\[ \binom{5}{-4} = 0 \][/tex]

2. Analyzing the Given Equation:
Since [tex]\( q = 0 \)[/tex], we substitute [tex]\( q \)[/tex] into [tex]\( r \cdot q \)[/tex]:
[tex]\[ r \cdot q = r \cdot 0 = 0 \][/tex]
However, it is given that [tex]\( r \cdot q = -2 \)[/tex]. This leads to a contradiction because any number multiplied by zero should result in zero, not [tex]\(-2\)[/tex]. Therefore, there seems to be an inconsistency in the problem as stated, and it cannot be solved with the given information.

### Problem 4:
Given two vectors:
[tex]\[ y = \begin{pmatrix} 3 - x \\ 5x - 2 \end{pmatrix}, \quad z = \begin{pmatrix} -1 \\ -1 \end{pmatrix} \][/tex]
we need to find the value of [tex]\( x \)[/tex] such that the dot product [tex]\( y \cdot z = -9 \)[/tex].

1. Compute the Dot Product:
The dot product of two vectors [tex]\( y \)[/tex] and [tex]\( z \)[/tex] is given by:
[tex]\[ y \cdot z = (3 - x)(-1) + (5x - 2)(-1) \][/tex]

2. Expand and Simplify:
[tex]\[ y \cdot z = - (3 - x) - (5x - 2) \][/tex]
[tex]\[ y \cdot z = -3 + x - 5x + 2 \][/tex]
[tex]\[ y \cdot z = -3 + 2 + x - 5x \][/tex]
[tex]\[ y \cdot z = -1 - 4x \][/tex]

3. Set Equal to the Given Value:
Given [tex]\( y \cdot z = -9 \)[/tex], we substitute and solve for [tex]\( x \)[/tex]:
[tex]\[ -1 - 4x = -9 \][/tex]
[tex]\[ -1 - 4x + 1 = -9 + 1 \][/tex]
[tex]\[ -4x = -8 \][/tex]
[tex]\[ x = 2 \][/tex]

So, the value of [tex]\( x \)[/tex] is [tex]\(\boxed{2}\)[/tex].

### Final Answers:
3. The value of [tex]\( a \)[/tex] cannot be determined due to an inconsistency in the provided information.
4. The value of [tex]\( x \)[/tex] is [tex]\(\boxed{2}\)[/tex].