Answer :
Certainly! Let's identify the necessary constraints for the manufacturer's production process.
We are given the following information:
- Each bottle of cappuccino (let's call it [tex]\( x \)[/tex]) requires 6 ounces of coffee and 2 ounces of milk, earning a profit of [tex]$\$[/tex]0.40[tex]$. - Each bottle of café au lait (let's call it \( y \)) requires 4 ounces of coffee and 4 ounces of milk, earning a profit of $[/tex]\[tex]$0.50$[/tex].
- The manufacturer has 720 ounces of coffee and 400 ounces of milk available daily.
- The manufacturer needs to produce at least 80 bottles of coffee drinks daily, combining both types.
Let's summarize these conditions into constraints:
1. Minimum Production Requirement: The manufacturer must produce at least 80 bottles (cappuccino and café au lait combined) each day.
[tex]\[ x + y \geq 80 \][/tex]
2. Coffee Supply Constraint: The total amount of coffee used by cappuccinos and cafés au lait should not exceed 720 ounces.
[tex]\[ 6x + 4y \leq 720 \][/tex]
3. Milk Supply Constraint: The total amount of milk used by cappuccinos and cafés au lait should not exceed 400 ounces.
[tex]\[ 2x + 4y \leq 400 \][/tex]
Now, assessing the given options:
- [tex]\( x + y \geq 80 \)[/tex]: This matches the minimum production requirement constraint.
- [tex]\( 0.4x + 0.5y \geq 100 \)[/tex]: This is not a valid constraint derived from the given information.
- [tex]\( 6x + 4y \leq 720 \)[/tex]: This matches the coffee supply constraint.
- [tex]\( 2x + 4y \leq 400 \)[/tex]: This matches the milk supply constraint.
- [tex]\( 6x + 2y \geq 720 \)[/tex]: This is not correct given the resource limitations.
- [tex]\( 4x + 4y \geq 400 \)[/tex]: This is not correct given the resource limitations.
Therefore, the correct constraints on the system, other than [tex]\( x \geq 0 \)[/tex] and [tex]\( y \geq 0 \)[/tex], are:
[tex]\[ x + y \geq 80 \][/tex]
[tex]\[ 6x + 4y \leq 720 \][/tex]
[tex]\[ 2x + 4y \leq 400 \][/tex]
These constraints ensure that the manufacturer meets the demand and stays within the available resources.
We are given the following information:
- Each bottle of cappuccino (let's call it [tex]\( x \)[/tex]) requires 6 ounces of coffee and 2 ounces of milk, earning a profit of [tex]$\$[/tex]0.40[tex]$. - Each bottle of café au lait (let's call it \( y \)) requires 4 ounces of coffee and 4 ounces of milk, earning a profit of $[/tex]\[tex]$0.50$[/tex].
- The manufacturer has 720 ounces of coffee and 400 ounces of milk available daily.
- The manufacturer needs to produce at least 80 bottles of coffee drinks daily, combining both types.
Let's summarize these conditions into constraints:
1. Minimum Production Requirement: The manufacturer must produce at least 80 bottles (cappuccino and café au lait combined) each day.
[tex]\[ x + y \geq 80 \][/tex]
2. Coffee Supply Constraint: The total amount of coffee used by cappuccinos and cafés au lait should not exceed 720 ounces.
[tex]\[ 6x + 4y \leq 720 \][/tex]
3. Milk Supply Constraint: The total amount of milk used by cappuccinos and cafés au lait should not exceed 400 ounces.
[tex]\[ 2x + 4y \leq 400 \][/tex]
Now, assessing the given options:
- [tex]\( x + y \geq 80 \)[/tex]: This matches the minimum production requirement constraint.
- [tex]\( 0.4x + 0.5y \geq 100 \)[/tex]: This is not a valid constraint derived from the given information.
- [tex]\( 6x + 4y \leq 720 \)[/tex]: This matches the coffee supply constraint.
- [tex]\( 2x + 4y \leq 400 \)[/tex]: This matches the milk supply constraint.
- [tex]\( 6x + 2y \geq 720 \)[/tex]: This is not correct given the resource limitations.
- [tex]\( 4x + 4y \geq 400 \)[/tex]: This is not correct given the resource limitations.
Therefore, the correct constraints on the system, other than [tex]\( x \geq 0 \)[/tex] and [tex]\( y \geq 0 \)[/tex], are:
[tex]\[ x + y \geq 80 \][/tex]
[tex]\[ 6x + 4y \leq 720 \][/tex]
[tex]\[ 2x + 4y \leq 400 \][/tex]
These constraints ensure that the manufacturer meets the demand and stays within the available resources.