In a species of plant, the allele for tall plants, [tex]$T$[/tex], is dominant over the allele for short plants, [tex]$t$[/tex]. The table shows the distribution of genotypes in a population of plants.

\begin{tabular}{|l|l|l|}
\hline Genotype & Phenotype & \begin{tabular}{l}
Number of \\
individuals
\end{tabular} \\
\hline
[tex]$T T$[/tex] & Tall & 26 \\
\hline
[tex]$T t$[/tex] & Tall & 64 \\
\hline
[tex]$t t$[/tex] & Short & 20 \\
\hline
\end{tabular}

What is the frequency of the [tex]$t$[/tex] allele?

Hint: There are a total of 220 alleles for this gene in the population.

A. 0.09
B. 0.47
C. 0.84
D. 0.20



Answer :

To determine the frequency of the [tex]$t$[/tex] allele in this population, we need to follow these steps:

1. Count the total number of alleles:

Given that each plant has 2 alleles, and there are 110 plants in total (26 with genotype [tex]\(TT\)[/tex], 64 with genotype [tex]\(Tt\)[/tex], and 20 with genotype [tex]\(tt\)[/tex]), the total number of alleles is:
[tex]\[ 110 \times 2 = 220 \][/tex]

2. Calculate the number of [tex]$t$[/tex] alleles:

- Plants with genotype [tex]\(TT\)[/tex] contribute 0 [tex]\(t\)[/tex] alleles.
- Plants with genotype [tex]\(Tt\)[/tex] each contribute 1 [tex]\(t\)[/tex] allele. Thus, the [tex]\(64\)[/tex] plants of genotype [tex]\(Tt\)[/tex] contribute:
[tex]\[ 64 \times 1 = 64 \ t\text{ alleles} \][/tex]
- Plants with genotype [tex]\(tt\)[/tex] each contribute 2 [tex]\(t\)[/tex] alleles. Thus, the [tex]\(20\)[/tex] plants of genotype [tex]\(tt\)[/tex] contribute:
[tex]\[ 20 \times 2 = 40 \ t\text{ alleles} \][/tex]

Combining these, the total number of [tex]\(t\)[/tex] alleles is:
[tex]\[ 0 + 64 + 40 = 104 \][/tex]

3. Determine the frequency of the [tex]$t$[/tex] allele:

The frequency of the [tex]$t$[/tex] allele is the number of [tex]\(t\)[/tex] alleles divided by the total number of alleles:
[tex]\[ \text{Frequency of } t = \frac{\text{Number of } t \text{ alleles}}{\text{Total number of alleles}} = \frac{104}{220} \][/tex]

Simplifying this fraction, we get:
[tex]\[ \frac{104}{220} \approx 0.4727 \][/tex]

Therefore, the frequency of the [tex]$t$[/tex] allele is approximately [tex]\(0.47\)[/tex]. Thus, the correct answer is:
[tex]\[ \boxed{0.47} \][/tex]

Hence, the answer is B.