Answer :

Sure! Let's solve the given linear equation step-by-step and verify the result.

The equation is:
[tex]\[ \frac{4m + 3}{7} + 2 = \frac{m + 5}{2} \][/tex]

### Step 1: Eliminate the fractions
To eliminate the fractions, we can multiply every term by the least common multiple (LCM) of the denominators. The denominators are 7 and 2, so the LCM is 14.

Multiply every term by 14:
[tex]\[ 14 \cdot \left(\frac{4m + 3}{7}\right) + 14 \cdot 2 = 14 \cdot \left(\frac{m + 5}{2}\right) \][/tex]

This simplifies to:
[tex]\[ 2(4m + 3) + 28 = 7(m + 5) \][/tex]

### Step 2: Distribute and simplify both sides
Distribute the constants inside the parentheses:
[tex]\[ 2 \cdot 4m + 2 \cdot 3 + 28 = 7 \cdot m + 7 \cdot 5 \][/tex]

This simplifies to:
[tex]\[ 8m + 6 + 28 = 7m + 35 \][/tex]

Combine like terms:
[tex]\[ 8m + 34 = 7m + 35 \][/tex]

### Step 3: Isolate the variable
To isolate [tex]\(m\)[/tex], subtract [tex]\(7m\)[/tex] from both sides:
[tex]\[ 8m - 7m + 34 = 35 \][/tex]

This simplifies to:
[tex]\[ m + 34 = 35 \][/tex]

Now, subtract 34 from both sides:
[tex]\[ m = 35 - 34 \][/tex]

This gives:
[tex]\[ m = 1 \][/tex]

### Step 4: Verify the solution
Substitute [tex]\(m = 1\)[/tex] back into the original equation to verify it satisfies the equation:
[tex]\[ \frac{4(1) + 3}{7} + 2 = \frac{1 + 5}{2} \][/tex]

Simplify inside each fraction:
[tex]\[ \frac{4 + 3}{7} + 2 = \frac{6}{2} \][/tex]

So,
[tex]\[ \frac{7}{7} + 2 = 3 \][/tex]

This simplifies to:
[tex]\[ 1 + 2 = 3 \][/tex]

Indeed, [tex]\(3 = 3\)[/tex] is true.

Therefore, the solution to the equation is:
[tex]\[ m = 1 \][/tex]

And we have verified that this value satisfies the original equation.