Question 8 of 10
What can you say about the end behavior of the function [tex]$f(x)=-4x^6-6x^2-52$[/tex]?

A. [tex]$f(x)$[/tex] is an even function so both ends of the graph go in the same direction.
B. [tex][tex]$f(x)$[/tex][/tex] is an even function so both ends of the graph go in opposite directions.
C. The leading coefficient is negative so the left end of the graph goes down.
D. The leading coefficient is negative so the left end of the graph goes up.



Answer :

To determine the end behavior of the function [tex]\( f(x) = -4x^6 - 6x^2 - 52 \)[/tex], we need to understand how polynomials behave as [tex]\( x \)[/tex] approaches positive and negative infinity.

1. Identify the Degree and Leading Coefficient:
- The polynomial function [tex]\( f(x) \)[/tex] has several terms, but the term with the highest degree will dominate the end behavior.
- The term with the highest degree is [tex]\( -4x^6 \)[/tex]. Thus, the degree of the polynomial is 6.
- The leading coefficient is the coefficient of this highest degree term, which is [tex]\(-4\)[/tex].

2. Determine Degree and Leading Coefficient Effect:
- The degree of the polynomial (6) is an even number. For polynomial functions, an even degree means that the ends of the polynomial will move in the same direction as [tex]\( x \)[/tex] approaches positive and negative infinity.
- The leading coefficient is [tex]\(-4\)[/tex], which is negative.

3. Analyze the End Behavior:
- When dealing with a polynomial where the leading degree term is of an even degree and has a negative leading coefficient, as [tex]\( x \)[/tex] approaches [tex]\( +\infty \)[/tex] or [tex]\( -\infty \)[/tex], the polynomial will head towards [tex]\( -\infty \)[/tex].
- This means that both ends of the graph will go downward.

Therefore, the correct assessment of the end behavior of the function [tex]\( f(x) = -4x^6 - 6x^2 - 52 \)[/tex] is that both ends of the graph go downwards.

So the correct answer is:

C. The leading coefficient is negative so the left end of the graph goes down.