What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures [tex]90^{\circ}[/tex]?

A. [tex]540^{\circ}[/tex]
B. [tex]180^{\circ}[/tex]
C. [tex]1080^{\circ}[/tex]
D. [tex]360^{\circ}[/tex]
E. [tex]720^{\circ}[/tex]
F. [tex]900^{\circ}[/tex]



Answer :

To determine the sum of the measures of the interior angles of a regular polygon where each exterior angle measures [tex]\(90^\circ\)[/tex], let's follow these steps:

### Step 1: Understand the Relationship Between Exterior Angles and Number of Sides
For any polygon, the sum of the exterior angles is always [tex]\(360^\circ\)[/tex]. To find the number of sides ([tex]\(n\)[/tex]) of the polygon, we can use the fact that:
[tex]\[ \text{Number of sides} = \frac{\text{Sum of exterior angles}}{\text{Measure of one exterior angle}} \][/tex]

Given that each exterior angle measures [tex]\(90^\circ\)[/tex], we can calculate:
[tex]\[ n = \frac{360^\circ}{90^\circ} = 4 \][/tex]
So, the polygon is a quadrilateral with 4 sides.

### Step 2: Calculate the Sum of Interior Angles
The sum of the interior angles of a polygon is given by the formula:
[tex]\[ \text{Sum of interior angles} = (n - 2) \times 180^\circ \][/tex]

For our quadrilateral (where [tex]\(n = 4\)[/tex]):
[tex]\[ \text{Sum of interior angles} = (4 - 2) \times 180^\circ = 2 \times 180^\circ = 360^\circ \][/tex]

### Conclusion
The sum of the measures of the interior angles of a regular polygon where each exterior angle measures [tex]\(90^\circ\)[/tex] is [tex]\(360^\circ\)[/tex].

Thus, the correct answer is:
D. [tex]\(360^\circ\)[/tex]