Given a [tex]$0.4^5$[/tex] caliber bullet ( [tex]$m = 0.162 \, \text{kg}$[/tex] ) leaving the muzzle of a gun at [tex]$800 \, \text{m/s}$[/tex]:

(Note: This question is incomplete and needs additional context or completion to make sense. A possible completion could be:)

Calculate the kinetic energy of the bullet as it leaves the muzzle of the gun.



Answer :

Sure, let's work through the problem step by step.

We are tasked with finding the kinetic energy of a bullet with a mass of 0.162 kg, traveling at a velocity of 800 m/s as it leaves the muzzle of a gun.

### Step-by-Step Solution:

1. Understand the problem:
- We need to find the kinetic energy of the bullet.
- The mass of the bullet, [tex]\( m \)[/tex], is 0.162 kg.
- The velocity of the bullet, [tex]\( v \)[/tex], is 800 m/s.

2. Know the formula:
- The formula for kinetic energy [tex]\( (KE) \)[/tex] is given by:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
- Here, [tex]\( m \)[/tex] is the mass of the object, and [tex]\( v \)[/tex] is its velocity.

3. Plug in the values:
- Substitute [tex]\( m = 0.162 \, \text{kg} \)[/tex] and [tex]\( v = 800 \, \text{m/s} \)[/tex] into the kinetic energy formula:
[tex]\[ KE = \frac{1}{2} \cdot 0.162 \, \text{kg} \cdot (800 \, \text{m/s})^2 \][/tex]

4. Calculate the velocity squared:
- First, calculate [tex]\( (800 \, \text{m/s})^2 \)[/tex]:
[tex]\[ (800 \, \text{m/s})^2 = 640000 \, \text{m}^2/\text{s}^2 \][/tex]

5. Calculate the product:
- Multiply [tex]\( 0.162 \)[/tex] by [tex]\( 640000 \)[/tex]:
[tex]\[ 0.162 \times 640000 = 103680 \, \text{kg} \cdot \text{m}^2/\text{s}^2 \][/tex]

6. Divide by 2:
- Finally, divide by 2 to get the kinetic energy:
[tex]\[ KE = \frac{103680}{2} = 51840 \, \text{J} \][/tex]

### Conclusion:
The kinetic energy of the bullet as it leaves the muzzle of the gun is [tex]\( 51840 \, \text{J} \)[/tex].