To solve for the values of [tex]\( y \)[/tex] given the equation [tex]\( y = 2x - 2 \)[/tex] and the values of [tex]\( x \)[/tex]:
1. Substitute [tex]\( x = -1 \)[/tex] into the equation:
[tex]\[
y = 2(-1) - 2 = -2 - 2 = -4
\][/tex]
2. Substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[
y = 2(0) - 2 = 0 - 2 = -2
\][/tex]
3. Substitute [tex]\( x = 1 \)[/tex] into the equation:
[tex]\[
y = 2(1) - 2 = 2 - 2 = 0
\][/tex]
4. Substitute [tex]\( x = 2 \)[/tex] into the equation:
[tex]\[
y = 2(2) - 2 = 4 - 2 = 2
\][/tex]
5. Substitute [tex]\( x = 3 \)[/tex] into the equation:
[tex]\[
y = 2(3) - 2 = 6 - 2 = 4
\][/tex]
6. Substitute [tex]\( x = 4 \)[/tex] into the equation:
[tex]\[
y = 2(4) - 2 = 8 - 2 = 6
\][/tex]
So, the completed table is:
[tex]\[
\begin{array}{l|l}
x & y \\
\hline
-1 & -4 \\
0 & -2 \\
1 & 0 \\
2 & 2 \\
3 & 4 \\
4 & 6 \\
\end{array}
\][/tex]
