Type the correct answer in the box. Give the answer to the correct number of significant figures.

The density is [tex]$\square \frac{\text { pounds }}{600 t ^2}$[/tex].



Answer :

To determine the density, we start with two given quantities: total mass and volume.

1. Total Mass: The total mass given is 600 pounds.
2. Volume: The volume given is 85 cubic feet.

Density (denoted as [tex]\( \rho \)[/tex]) is calculated using the formula:
[tex]\[ \rho = \frac{\text{mass}}{\text{volume}} \][/tex]

Plugging in the given values:
[tex]\[ \rho = \frac{600 \text{ pounds}}{85 \text{ cubic feet}} \][/tex]

Performing the division:
[tex]\[ \rho = 7.06 \text{ pounds per cubic foot} \][/tex]

Given the context, the units should be adjusted. The question mentions a unit of pounds per [tex]\( 600 t^2 \)[/tex]. However, typically, the unit of density derived in this type of problem would be pounds per cubic foot.

However, based on the constraint (place the correct numeric answer in the density box):

The result is:
[tex]\[ \boxed{7.06} \quad \frac{\text{ pounds }}{600 t ^2} \][/tex]

(Note: It is understood that there is a mistake in the unit [tex]\(600 t^2\)[/tex], and it should likely be [tex]\(\frac{\text{ pounds }}{\text{ cubic feet }}\)[/tex], or this might be a hypothetical unit given in the problem.)

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