(b) The table shows the student's results.

\begin{tabular}{|l|c|}
\cline { 2 - 2 } \multicolumn{1}{c|}{} & Mass in g \\
\hline Beaker [tex]$A$[/tex] and contents before mixing & 128.71 \\
\hline Beaker [tex]$B$[/tex] and contents before mixing & 128.97 \\
\hline Beaker [tex]$A$[/tex] and contents after mixing & 154.10 \\
\hline Beaker [tex]$B$[/tex] after mixing & 103.58 \\
\hline
\end{tabular}

Show that the law of conservation of mass is true using the data from the table above.



Answer :

To demonstrate that the law of conservation of mass is true using the given data, we need to compare the total mass of the substances before mixing and after mixing. The law of conservation of mass states that the total mass of a closed system remains constant over time, as long as no mass is added or removed from the system.

Here is the step-by-step solution:

1. Determine the total mass before mixing:
- Mass of Beaker A and contents before mixing: [tex]\( 128.71 \)[/tex] g
- Mass of Beaker B and contents before mixing: [tex]\( 128.97 \)[/tex] g

To find the total mass before mixing, we add these two masses together:
[tex]\[ \text{Total mass before mixing} = 128.71 \text{ g} + 128.97 \text{ g} = 257.68 \text{ g} \][/tex]

2. Determine the total mass after mixing:
- Mass of Beaker A and contents after mixing: [tex]\( 154.10 \)[/tex] g
- Mass of Beaker B and contents after mixing: [tex]\( 103.58 \)[/tex] g

To find the total mass after mixing, we add these two masses together:
[tex]\[ \text{Total mass after mixing} = 154.10 \text{ g} + 103.58 \text{ g} = 257.68 \text{ g} \][/tex]

3. Compare the total masses before and after mixing:
- Total mass before mixing: [tex]\( 257.68 \)[/tex] g
- Total mass after mixing: [tex]\( 257.68 \)[/tex] g

These two masses are equal, indicating that no mass was lost or gained during the mixing process.

Thus, the total mass of the system remained constant before and after the mixing, showing that the law of conservation of mass holds true for this set of data.