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Briana has [tex]\( 4 \frac{1}{2} \)[/tex] cups of oats. She uses [tex]\( 2 \frac{1}{4} \)[/tex] cups of oats to make oatmeal raisin cookies, then borrows 1 cup of oats from her neighbor. Her recipe for granola calls for [tex]\( 2 \frac{1}{2} \)[/tex] cups of oats. Does she have enough? How much will she have left over, or how much more will she need?

A. Yes, she has 1 cup left.
B. No, she needs 1 cup more.
C. Yes, she has [tex]\( \frac{3}{4} \)[/tex] cup left.
D. No, she needs [tex]\( \frac{3}{4} \)[/tex] cup more.



Answer :

GinnyAnswer
Let's break down the problem step-by-step to determine if Briana has enough oats for her granola recipe and how much she will have left over or need.

1. Initial Quantity of Oats:
Briana starts with [tex]\(4 \frac{1}{2}\)[/tex] cups of oats. Converting this to a decimal, we get:
[tex]\[ 4 \frac{1}{2} = 4.5 \text{ cups} \][/tex]

2. Oats Used for Oatmeal-Raisin Cookies:
She uses [tex]\(2 \frac{1}{4}\)[/tex] cups of oats. Converting this to a decimal, we get:
[tex]\[ 2 \frac{1}{4} = 2.25 \text{ cups} \][/tex]

3. Oats After Making Cookies:
Subtract the oats used for the cookies from the initial quantity:
[tex]\[ 4.5 - 2.25 = 2.25 \text{ cups} \][/tex]

4. Oats Borrowed from Neighbor:
Briana borrows 1 cup of oats from her neighbor, so:
[tex]\[ 2.25 + 1 = 3.25 \text{ cups} \][/tex]

5. Oats Needed for Granola Recipe:
Her granola recipe calls for [tex]\(2 \frac{1}{2}\)[/tex] cups of oats. Converting this to a decimal:
[tex]\[ 2 \frac{1}{2} = 2.5 \text{ cups} \][/tex]

6. Check if Briana has Enough Oats:
Compare the oats she has (3.25 cups) with the oats needed (2.5 cups):
[tex]\[ 3.25 \geq 2.5 \][/tex]
Since 3.25 is greater than 2.5, Briana has enough oats for the granola.

7. Determine Leftover Oats:
Calculate how much oats she will have left after making the granola:
[tex]\[ 3.25 - 2.5 = 0.75 \text{ cups} \][/tex]

Therefore, Briana has enough oats for her granola recipe and will have [tex]\( \frac{3}{4} \)[/tex] cup left over.

The correct answer is:
(C) Yes, she has [tex]\( \frac{3}{4} \)[/tex] cup left.

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