TALLER DE ESTEQUIOMETRÍA PARA NOVENOS

a) Calcular la cantidad de gramos de Magnesio que reaccionan con 80 g de HCl según la ecuación:

Ácido Clorhídrico + Magnesio → Cloruro de Magnesio (II) + Hidrógeno



Answer :

Final answer:

The answer explains how to calculate the grams of Magnesium that react with 80g of HCl based on the balanced chemical equation and mole ratios.


Explanation:

The balanced chemical equation for the reaction:
2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g)

To calculate the grams of Magnesium reacting with 80g of HCl:
Given 0.08 moles of MgCl2 are formed, the molar ratio is 1:2 for HCl:Mg, so 0.04 moles of Mg are used. This is equal to 1.22 grams of Mg reacting with 80g of HCl.

Conclusion:
1.22 grams of Magnesium react with 80g of HCl according to the given chemical equation.


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