To determine the correct products for the reaction between sodium bicarbonate (NaHCO₃) and acetic acid (HC₂H₃O₂), we'll analyze the possible outcomes of the reaction.
The reaction typically involves the formation of sodium acetate (NaC₂H₃O₂), carbon dioxide (CO₂), and water (H₂O). Here's the step-by-step reasoning:
1. Sodium Bicarbonate (NaHCO₃) and Acetic Acid (HC₂H₃O₂):
- Sodium bicarbonate is a common base, and acetic acid is a weak acid.
- When a base reacts with an acid, they typically undergo a neutralization reaction to form a salt, water, and sometimes a gas.
2. Prediction of Products:
- Sodium bicarbonate can produce carbon dioxide gas because it contains the bicarbonate ion (HCO₃⁻), which decomposes upon reaction with an acid.
- The products typically include a salt (sodium acetate in this case), water, and carbon dioxide.
3. Writing the Balanced Equation:
- Initially, write the reactants and potential products before balancing:
[tex]\[
\text{NaHCO}_3 + \text{HC}_2\text{H}_3\text{O}_2 \rightarrow \text{NaC}_2\text{H}_3\text{O}_2 + \text{CO}_2 + \text{H}_2\text{O}
\][/tex]
4. Verification with Possible Answer Choices:
- NaC₂H₃O₂ + H₂O: This option misses carbon dioxide, which is a common product in reactions involving bicarbonate.
- NaC₂H₃O₂ + CO₂ + H₂O: This option includes all expected products: the salt (sodium acetate), carbon dioxide, and water.
- NaC₂H₃O₂ + H₂: Hydrogen gas is not typically evolved in this reaction.
5. Conclusion:
The correct products that complete the reaction, considering all possible products and typical reaction behavior, are:
[tex]\[
\text{NaC}_2\text{H}_3\text{O}_2 + \text{CO}_2 + \text{H}_2\text{O}
\][/tex]
Based on our analysis, the correct answer is the second option:
[tex]\[
\boxed{2}
\][/tex]
