The Richter scale measures the magnitude, [tex]M[/tex], of an earthquake as a function of its intensity, [tex]I[/tex], and the intensity of a reference earthquake, [tex]I_0[/tex].

[tex]\[ M = \log \left(\frac{I}{I_0}\right) \][/tex]

What is the approximate intensity of an earthquake with a Richter scale magnitude of 4.8? Use a reference intensity of 1.

A. 0.681

B. [tex]$8,492,500$[/tex]

C. 63,096

D. 660,057



Answer :

To determine the approximate intensity, [tex]\( I \)[/tex], of an earthquake with a Richter scale magnitude of 4.8, given that the reference intensity, [tex]\( I_0 \)[/tex], is 1, we can use the Richter scale formula.

The formula for the Richter scale magnitude [tex]\( M \)[/tex] is:

[tex]\[ M = \log_{10} \left( \frac{I}{I_0} \right) \][/tex]

We are given:
- [tex]\( M = 4.8 \)[/tex]
- [tex]\( I_0 = 1 \)[/tex]

First, we need to isolate [tex]\( I \)[/tex] in this equation. Starting from the given formula:

[tex]\[ 4.8 = \log_{10} \left( \frac{I}{I_0} \right) \][/tex]

Since [tex]\( I_0 = 1 \)[/tex], this simplifies to:

[tex]\[ 4.8 = \log_{10} (I) \][/tex]

To solve for [tex]\( I \)[/tex], we need to rewrite the logarithmic equation in its exponential form. The equation [tex]\( \log_{10} (I) = 4.8 \)[/tex] can be rewritten as:

[tex]\[ I = 10^{4.8} \][/tex]

Now we calculate [tex]\( 10^{4.8} \)[/tex]:

[tex]\[ I \approx 10^{4.8} \approx 63095.7344480193 \][/tex]

Thus, the intensity [tex]\( I \)[/tex] of the earthquake is approximately 63,095. Therefore, the correct answer is:

C. 63,096