The table below shows four samples of carbon dioxide and the temperature of the water that they were dissolved in.

\begin{tabular}{|c|c|}
\hline
Sample & Temperature of water [tex]$\left({ }^{\circ} C \right)$[/tex] \\
\hline
1 & 78 \\
\hline
2 & 73 \\
\hline
3 & 55 \\
\hline
4 & 63 \\
\hline
\end{tabular}

Which of the samples most likely had the lowest solubility?

A. 1
B. 2
C. 3
D. 4



Answer :

To determine which sample most likely had the lowest solubility of carbon dioxide, we need to understand the relationship between the solubility of gases in liquids and temperature. Typically, for gases dissolved in liquids, an increase in temperature results in decreased solubility. Thus, the sample with the highest temperature will have the lowest solubility.

We are given the following temperatures for each sample:

- Sample 1: 78°C
- Sample 2: 73°C
- Sample 3: 55°C
- Sample 4: 63°C

Let's find the sample with the highest temperature, as this sample will likely have the lowest solubility:

1. Sample 1 has a temperature of 78°C.
2. Sample 2 has a temperature of 73°C.
3. Sample 3 has a temperature of 55°C.
4. Sample 4 has a temperature of 63°C.

Comparing these temperatures, it is evident that 78°C is the highest temperature. Therefore, Sample 1 has the highest temperature.

Since the solubility of gases decreases with increasing temperature, the sample with the highest temperature (Sample 1) will have the lowest solubility.

Thus, the sample that most likely had the lowest solubility is:

Sample 1