Answered

Find the point [tex]\( P \)[/tex] on the graph of the function [tex]\( y=\sqrt{x} \)[/tex] closest to the point [tex]\( (3,0) \)[/tex].

The [tex]\( x \)[/tex] coordinate of [tex]\( P \)[/tex] is: [tex]\(\square\)[/tex]



Answer :

To find the point [tex]\( P \)[/tex] on the graph of the function [tex]\( y = \sqrt{x} \)[/tex] that is closest to the point [tex]\( (3, 0) \)[/tex], we need to minimize the distance between any point on the curve [tex]\( (x, \sqrt{x}) \)[/tex] and the point [tex]\( (3, 0) \)[/tex].

Let's denote the distance between a point [tex]\( (x, \sqrt{x}) \)[/tex] on the curve and the point [tex]\( (3, 0) \)[/tex] as [tex]\( D \)[/tex].

First, we write the distance formula [tex]\( D \)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex]:
[tex]\[ D = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} \][/tex]

Substituting [tex]\( (x_1, y_1) = (x, \sqrt{x}) \)[/tex] and [tex]\( (x_2, y_2) = (3, 0) \)[/tex], we get:
[tex]\[ D = \sqrt{(x - 3)^2 + (\sqrt{x} - 0)^2} \][/tex]

Simplify the expression:
[tex]\[ D = \sqrt{(x - 3)^2 + (\sqrt{x})^2} \][/tex]

Since [tex]\((\sqrt{x})^2 = x\)[/tex], we can rewrite [tex]\( D \)[/tex] as:
[tex]\[ D = \sqrt{(x - 3)^2 + x} \][/tex]

To find the minimum distance, we need to find the [tex]\( x \)[/tex] value that minimizes this distance function. Through optimization techniques and calculations, the [tex]\( x \)[/tex]-coordinate of point [tex]\( P \)[/tex] is found to be:

[tex]\[ x = 2.4999999114637803 \][/tex]

Therefore, the [tex]\( x \)[/tex]-coordinate of the point [tex]\( P \)[/tex] on the graph of [tex]\( y = \sqrt{x} \)[/tex] that is closest to the point [tex]\( (3, 0) \)[/tex] is approximately:
[tex]\[ x \approx 2.5 \][/tex]