Answer :

To solve the equation [tex]\(7^{-x+5} = 13^{-6x}\)[/tex] for [tex]\(x\)[/tex], we will utilize the properties of logarithms. Here's the step-by-step process:

1. Take the Natural Logarithm of Both Sides:
[tex]\[ \ln(7^{-x+5}) = \ln(13^{-6x}) \][/tex]

2. Apply the Power Rule of Logarithms:
The power rule states [tex]\(\ln(a^b) = b \ln(a)\)[/tex]. Therefore, we can rewrite our equation as:
[tex]\[ (-x+5) \ln(7) = (-6x) \ln(13) \][/tex]

3. Expand and Simplify the Equation:
Distribute the logarithms on both sides:
[tex]\[ -x \ln(7) + 5 \ln(7) = -6x \ln(13) \][/tex]

4. Rearrange to Isolate Terms Involving [tex]\(x\)[/tex]:
Bring all the terms involving [tex]\(x\)[/tex] on one side:
[tex]\[ 5 \ln(7) = x \ln(7) - 6x \ln(13) \][/tex]

5. Factor Out [tex]\(x\)[/tex] from the Right Side:
[tex]\[ 5 \ln(7) = x (\ln(7) - 6 \ln(13)) \][/tex]

6. Solve for [tex]\(x\)[/tex]:
Divide both sides by [tex]\((\ln(7) - 6 \ln(13))\)[/tex]:
[tex]\[ x = \frac{5 \ln(7)}{\ln(7) - 6 \ln(13)} \][/tex]

Therefore, the exact value of [tex]\(x\)[/tex] in terms of natural logarithms (base-e) is:
[tex]\[ x = \frac{5 \ln(7)}{\ln(7) - 6 \ln(13)} \][/tex]

After evaluating this expression numerically, [tex]\(x\)[/tex] is approximately:
[tex]\[ x \approx -0.7237210372419273 \][/tex]

To summarize, the exact solution for [tex]\(x\)[/tex] is:
[tex]\[ x = \frac{5 \ln(7)}{\ln(7) - 6 \ln(13)} \][/tex]