Answer :
To determine the hydronium ion concentration in milk given a pH of 8.2, follow these steps:
1. Recall the formula that relates pH to hydronium ion concentration: [tex]\([H_3O^+] = 10^{-\text{pH}}\)[/tex].
2. Substitute the given pH value into the formula:
[tex]\[ [H_3O^+] = 10^{-8.2} \][/tex]
3. Calculate the value of [tex]\(10^{-8.2}\)[/tex]. This can be evaluated as approximately:
[tex]\[ [H_3O^+] \approx 6.31 \times 10^{-9} \][/tex]
4. Now, compare the calculated value with the given choices:
- A. [tex]\(2.75 \times 10^{-4}\)[/tex]
- B. [tex]\(6.31 \times 10^{-9}\)[/tex]
- C. [tex]\(3.64 \times 10^3\)[/tex]
- D. [tex]\(1.58 \times 10^8\)[/tex]
5. The calculated hydronium ion concentration [tex]\(6.31 \times 10^{-9}\)[/tex] matches choice B.
Therefore, the correct answer is:
B. [tex]\(6.31 \times 10^{-9}\)[/tex]
1. Recall the formula that relates pH to hydronium ion concentration: [tex]\([H_3O^+] = 10^{-\text{pH}}\)[/tex].
2. Substitute the given pH value into the formula:
[tex]\[ [H_3O^+] = 10^{-8.2} \][/tex]
3. Calculate the value of [tex]\(10^{-8.2}\)[/tex]. This can be evaluated as approximately:
[tex]\[ [H_3O^+] \approx 6.31 \times 10^{-9} \][/tex]
4. Now, compare the calculated value with the given choices:
- A. [tex]\(2.75 \times 10^{-4}\)[/tex]
- B. [tex]\(6.31 \times 10^{-9}\)[/tex]
- C. [tex]\(3.64 \times 10^3\)[/tex]
- D. [tex]\(1.58 \times 10^8\)[/tex]
5. The calculated hydronium ion concentration [tex]\(6.31 \times 10^{-9}\)[/tex] matches choice B.
Therefore, the correct answer is:
B. [tex]\(6.31 \times 10^{-9}\)[/tex]